计算具有多个键的数组中的出现次数
Counting occurrences in an array that has more than 1 key
我正在尝试获取包含第 1 个键值的数组的出现次数,例如:
$newarray[0] = [
'id' => '2',
'date' => '2016-04-22'
];
$newarray[1] = [
'id' => '2',
'date' => '2016-04-13'
];
$newarray[2] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[3] = [
'id' => '1',
'date' => '2016-03-11'
];
$newarray[4] = [
'id' => '2',
'date' => '2016-03-05'
];
$newarray[5] = [
'id' => '1',
'date' => '2016-03-01'
];
我想把它改成这样:
Array ( [0] => Array ( [id] => 1 [date] => 2016-03-11 [occurences] => 2 ) [1] => Array ( [id] => 2 [date] => 2016-04-22 [occurences] => 4 ) )
我试过这样做:
$cleanarray;
$newarray2=$newarray;
$newarray;
$k=0;
$num=1;
for($i=0; $i<count($newarray); $i++){
for($j=1; $j<count($newarray2); $j++){
if($newarray2[$j]["id"]==$newarray[$i]["id"]){
$num++;
}
}
$cleanarray[$k] = [
'id' => $newarray[$i]["id"],
'date' => $newarray[$i]["date"],
'occurences' => $num
];
$k++;
$num=0;
}
但是很多项目重复,相同的出现但是多次,在其他情况下重复的项目(具有相同的id)会有不同的出现,所以我不知道我能做什么,我知道有一个功能:
$occurences = array_count_values($array);
但是在这种情况下它不起作用,我该如何解决?
你可以像下面那样做:-
$final_array = array();
foreach($newarray as $arr){
if(!in_array($arr['id'],array_keys($final_array))){
$final_array[$arr['id']] = $arr;
$final_array[$arr['id']]['occurences'] = 1;
}else{
$final_array[$arr['id']]['occurences'] += 1;
}
}
$final_array= array_values($final_array);
print_r($final_array);
注意:- 如果您希望最终数组为 id 的升序,请使用如下 usort() 函数:-
function cmpId($a, $b) {
return ($a['id'] - $b['id']);
}
usort($final_array, "cmpId");
print_r($final_array);
我知道你在找什么,但我认为这可以解决你的问题:
$newarray[0] = [
'id' => '2',
'date' => '2016-04-22'
];
$newarray[1] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[2] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[3] = [
'id' => '1',
'date' => '2016-03-11'
];
$newarray[4] = [
'id' => '2',
'date' => '2016-03-05'
];
$newarray[5] = [
'id' => '1',
'date' => '2016-03-01'
];
foreach($newarray as $key => $value){
if(isset($found[$value['id']][$value['date']])) {
$found[$value['id']][$value['date']]++;
} else {
$found[$value['id']][$value['date']] = 1;
}
}
print_r($found);
这将 return 类似于:-
Array
(
[2] => Array
(
[2016-04-22] => 1
[2016-04-12] => 2
[2016-03-05] => 1
)
[1] => Array
(
[2016-03-11] => 1
[2016-03-01] => 1
)
)
在此过程中使用临时密钥将是最高效的方式。临时键简化了输出数组任务,需要更少和更快的检查。如果您希望在生成结果数组后对 id
进行排序,临时键允许一个简单的 ksort()
调用。
代码:(Demo)
$newarray=[
['id' => '2','date' => '2016-04-22'],
['id' => '2','date' => '2016-04-13'],
['id' => '2','date' => '2016-04-12'],
['id' => '1','date' => '2016-03-11'],
['id' => '2','date' => '2016-03-05'],
['id' => '1','date' => '2016-03-01']
];
foreach($newarray as $a){
if(!isset($result[$a['id']])){
$result[$a['id']]=array_merge($a,['occurrences'=>1]); // use id as temp key, preserve first found date
}else{
++$result[$a['id']]['occurrences']; // only update occurrences to preserve date
}
}
ksort($result); // optionally sort on id ASC
var_export(array_values($result)); // remove temporary keys from first level and print to screen
输出:
array (
0 =>
array (
'id' => '1',
'date' => '2016-03-11',
'occurrences' => 2,
),
1 =>
array (
'id' => '2',
'date' => '2016-04-22',
'occurrences' => 4,
),
)
我正在尝试获取包含第 1 个键值的数组的出现次数,例如:
$newarray[0] = [
'id' => '2',
'date' => '2016-04-22'
];
$newarray[1] = [
'id' => '2',
'date' => '2016-04-13'
];
$newarray[2] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[3] = [
'id' => '1',
'date' => '2016-03-11'
];
$newarray[4] = [
'id' => '2',
'date' => '2016-03-05'
];
$newarray[5] = [
'id' => '1',
'date' => '2016-03-01'
];
我想把它改成这样:
Array ( [0] => Array ( [id] => 1 [date] => 2016-03-11 [occurences] => 2 ) [1] => Array ( [id] => 2 [date] => 2016-04-22 [occurences] => 4 ) )
我试过这样做:
$cleanarray;
$newarray2=$newarray;
$newarray;
$k=0;
$num=1;
for($i=0; $i<count($newarray); $i++){
for($j=1; $j<count($newarray2); $j++){
if($newarray2[$j]["id"]==$newarray[$i]["id"]){
$num++;
}
}
$cleanarray[$k] = [
'id' => $newarray[$i]["id"],
'date' => $newarray[$i]["date"],
'occurences' => $num
];
$k++;
$num=0;
}
但是很多项目重复,相同的出现但是多次,在其他情况下重复的项目(具有相同的id)会有不同的出现,所以我不知道我能做什么,我知道有一个功能:
$occurences = array_count_values($array);
但是在这种情况下它不起作用,我该如何解决?
你可以像下面那样做:-
$final_array = array();
foreach($newarray as $arr){
if(!in_array($arr['id'],array_keys($final_array))){
$final_array[$arr['id']] = $arr;
$final_array[$arr['id']]['occurences'] = 1;
}else{
$final_array[$arr['id']]['occurences'] += 1;
}
}
$final_array= array_values($final_array);
print_r($final_array);
注意:- 如果您希望最终数组为 id 的升序,请使用如下 usort() 函数:-
function cmpId($a, $b) {
return ($a['id'] - $b['id']);
}
usort($final_array, "cmpId");
print_r($final_array);
我知道你在找什么,但我认为这可以解决你的问题:
$newarray[0] = [
'id' => '2',
'date' => '2016-04-22'
];
$newarray[1] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[2] = [
'id' => '2',
'date' => '2016-04-12'
];
$newarray[3] = [
'id' => '1',
'date' => '2016-03-11'
];
$newarray[4] = [
'id' => '2',
'date' => '2016-03-05'
];
$newarray[5] = [
'id' => '1',
'date' => '2016-03-01'
];
foreach($newarray as $key => $value){
if(isset($found[$value['id']][$value['date']])) {
$found[$value['id']][$value['date']]++;
} else {
$found[$value['id']][$value['date']] = 1;
}
}
print_r($found);
这将 return 类似于:-
Array
(
[2] => Array
(
[2016-04-22] => 1
[2016-04-12] => 2
[2016-03-05] => 1
)
[1] => Array
(
[2016-03-11] => 1
[2016-03-01] => 1
)
)
在此过程中使用临时密钥将是最高效的方式。临时键简化了输出数组任务,需要更少和更快的检查。如果您希望在生成结果数组后对 id
进行排序,临时键允许一个简单的 ksort()
调用。
代码:(Demo)
$newarray=[
['id' => '2','date' => '2016-04-22'],
['id' => '2','date' => '2016-04-13'],
['id' => '2','date' => '2016-04-12'],
['id' => '1','date' => '2016-03-11'],
['id' => '2','date' => '2016-03-05'],
['id' => '1','date' => '2016-03-01']
];
foreach($newarray as $a){
if(!isset($result[$a['id']])){
$result[$a['id']]=array_merge($a,['occurrences'=>1]); // use id as temp key, preserve first found date
}else{
++$result[$a['id']]['occurrences']; // only update occurrences to preserve date
}
}
ksort($result); // optionally sort on id ASC
var_export(array_values($result)); // remove temporary keys from first level and print to screen
输出:
array (
0 =>
array (
'id' => '1',
'date' => '2016-03-11',
'occurrences' => 2,
),
1 =>
array (
'id' => '2',
'date' => '2016-04-22',
'occurrences' => 4,
),
)