根据字段中的值删除重复行

Remove duplicate rows based on a value in a field

我有一个非常大的table(几百万条记录)。一些记录有重复项(基于 FieldA),其中唯一的区别是 FiedldB 中的值。我想创建一个查询,该查询将删除所有基于 FieldA 的重复记录,保留 FieldB 中具有最低值的记录。这可能吗?

提取这些值似乎非常简单:

select distinct a, 
       min(b)   b 
from t
group by a;

Fiddle 例如:http://sqlfiddle.com/#!9/bc4c9/3

您应该可以从中调整删除方法。

CREATE TABLE TABLE1
  (
    FieldA VARCHAR2(30),
    FieldB VARCHAR2(30),
    FieldC VARCHAR2(30)
  );

INSERT INTO TABLE1 VALUES
  ('DUMMYDATA-A1','DUMMYDATA-B1','DUMMYDATA-C1'
  );
INSERT INTO TABLE1 VALUES
  ('DUMMYDATA-A1','DUMMYDATA-B4','DUMMYDATA-C1'
  );
INSERT INTO TABLE1 VALUES
  ('DUMMYDATA-A1','DUMMYDATA-B3','DUMMYDATA-C1'
  );
INSERT INTO TABLE1 VALUES
  ('DUMMYDATA-A1','DUMMYDATA-B2','DUMMYDATA-C1'
  );
COMMIT;

SELECT FieldA,
  FieldB,
  FieldC,
  RANK() OVER( PARTITION BY FieldA ORDER BY FieldB ASC) AS COLUMN_ALIAS
FROM TABLE1; --IDENTIFIES DUPLICATES BASED ON RANK VALUE

---PERFORM DELETE
DELETE
FROM TABLE1
WHERE ROWID IN
  (SELECT ROWID
  FROM
    (SELECT ROWID,
      RANK() OVER( PARTITION BY FieldA ORDER BY FieldB ASC) AS COLUMN_ALIAS
    FROM TABLE1
    )
  WHERE COLUMN_ALIAS>1
  );

COMMIT;

SELECT * FROM TABLE1; -- CONTAINS A SINGLE RECORD

RANK函数可以识别重复的记录,便于只删除重复的记录,保留原来的行。这已经在这里讨论过:Deleting duplicates rows from oracle。希望这有帮助

但是由于DELETE本身比较慢,可以在这种情况下(包含数百万条记录)在INSERT处实施适当的约束以避免重复输入。