Sangria-graphql：将 derivedInputObjectType 作为突变参数传递时出错

Question

我有以下情况 class 带有选项字段：

case class BusinessUserRow(id: String, firstName: Option[String], lastName: Option[String], email: Option[String])

我正在尝试为业务用户对象创建一个 inputType 对象

val BusinessUserInputType =
    deriveInputObjectType[BusinessUserRow](
      InputObjectTypeName("input"),
      InputObjectTypeDescription("A Business user")
    )

我想将此 BusinessInputObject 作为参数传递给 addBusinessUser 突变

  val businessUserInputArg = Argument("input", BusinessUserInputType)

val Mutation = ObjectType("Mutation", fields[RepoContext, Unit](
    Field("addBusinessUser", BusinessUserType,
      arguments = businessUserInputArg :: Nil,
      resolve = c ⇒ c.ctx.BusinessUserRepo.create(c.arg(businessUserInputArg)))))

但是我得到以下编译错误：

Type dao.Tables.BusinessUserRow @@ sangria.marshalling.FromInput.InputObjectResult cannot be used as an input. Please consider defining an implicit instance of `FromInput` for it.
[error]   val businessUserInputArg = Argument("input", BusinessUserInputType)

但是 BusinessRow 中的所有字段都是标量值。我不明白是什么导致 issue.Is 有什么我没有看到？

Answer 1

为了反序列化 BusinessUserRow 案例 class 中的输入，您需要提供 FromInput[BusinessUserRow] 类型 class 的实例。您可以在此处找到更多文档：

http://sangria-graphql.org/learn/#frominput-type-class

因此，例如，如果您使用 spray-json，那么您需要为 BusinessUserRow

定义 JsonFormat

Answer 2

谢谢！只需添加此行即可解决我的问题：

implicit val businessUserFormat = Json.format[BusinessUserRow]

Sangria-graphql：将 derivedInputObjectType 作为突变参数传递时出错

Sangria-graphql: error when passing in derivedInputObjectType as an mutation argument

scala

graphql

sangria