在表单中创建按钮以从 Odoo v8 中的表单创建新记录副本

Question

我在 Odoo v8.0 中创建模块。在模块中，我有一个模型（名为 cronograma）我在视图表单中创建了一个按钮，当 clic 尝试在模块中创建新记录时，复制一些特定字段并将这些字段添加到新记录中。

这是按钮的代码：

    # code of botton who invoke more date therapy
@api.model
@api.multi
def generate_record_name(self, values):
    # Override the original create function for the cronograma.cronograma model
    record = super(cronograma, self).create(values)
    # values to pass for record in new add to database
    record['paciente_id',
           'Nombre',
           'start_date',
           'start_time',
           'duration',
           'end_date',
           'Neuro',
           'Fisio',
           'Logo',
           'TS',
           'TO',] = True
    # return record whit the same form
    return record

这是错误消息：

Odoo Server Error

Traceback (most recent call last):
  File "/opt/odoo/odoo-server/openerp/http.py", line 546, in _handle_exception
    return super(JsonRequest, self)._handle_exception(exception)
  File "/opt/odoo/odoo-server/openerp/http.py", line 583, in dispatch
    result = self._call_function(**self.params)
  File "/opt/odoo/odoo-server/openerp/http.py", line 319, in _call_function
    return checked_call(self.db, *args, **kwargs)
  File "/opt/odoo/odoo-server/openerp/service/model.py", line 118, in wrapper
    return f(dbname, *args, **kwargs)
  File "/opt/odoo/odoo-server/openerp/http.py", line 316, in checked_call
    return self.endpoint(*a, **kw)
  File "/opt/odoo/odoo-server/openerp/http.py", line 812, in __call__
    return self.method(*args, **kw)
  File "/opt/odoo/odoo-server/openerp/http.py", line 412, in response_wrap
    response = f(*args, **kw)
  File "/opt/odoo/odoo-server/addons/web/controllers/main.py", line 948, in call_button
    action = self._call_kw(model, method, args, {})
  File "/opt/odoo/odoo-server/addons/web/controllers/main.py", line 936, in _call_kw
    return getattr(request.registry.get(model), method)(request.cr, request.uid, *args, **kwargs)
  File "/opt/odoo/odoo-server/openerp/api.py", line 268, in wrapper
    return old_api(self, *args, **kwargs)
  File "/opt/odoo/odoo-server/openerp/api.py", line 371, in old_api
    recs = self.browse(cr, uid, [], context)
  File "/opt/odoo/odoo-server/openerp/api.py", line 268, in wrapper
    return old_api(self, *args, **kwargs)
  File "/opt/odoo/odoo-server/openerp/models.py", line 5282, in browse
    return self._browse(Environment(cr, uid, context or {}), ids)
  File "/opt/odoo/odoo-server/openerp/api.py", line 769, in __new__
    self.cr, self.uid, self.context = self.args = (cr, uid, frozendict(context))
TypeError: cannot convert dictionary update sequence element #0 to a sequence

关于项目的数据：

S.O: Ubuntu 14.04
Virtualization: Yes
ERP: Odoo v8.0
Language: Python 2.7

亲切的问候， Marco García Baturan.

Answer 1

我不太明白你想用这段代码做什么，但这里有一些问题：

您不能同时使用装饰器 @api.model 和 @api.multi。 api.multi 用于在记录集上循环的函数，而 api.model 用于不依赖于记录集的函数。这两个不能一起用
如果这是一个按钮函数，vals 参数是什么？什么都不会通过。
您不能为这样的记录编制索引：

记录[...]

我不太明白那是什么意思，但是如果你想写入字段，你应该使用 record.write() 方法，并以字典作为参数。

我建议在尝试使用 orm api.

创建模块之前阅读 documentation 和模块创建指南

在表单中创建按钮以从 Odoo v8 中的表单创建新记录副本

Create button in form to create new record copy from the form in Odoo v8

ubuntu

python-2.7

odoo-8