如果您从单个列获取数据，如何创建连接列？

Question

我有一个名为 Issue_Status 的专栏，它介绍了与风险管理相关的问题的当前状态。我需要在两个 Cognos and/or SQL 服务器中创建一个新列，以显示问题的所有先前状态的串联列。它是这样的。

现在，我没有 Issue_Status_Concatenated。

事情是这样的。

Issue I.D   Issue Status   

1234        Draft           
1234        Open           
1234        Closed          
5678        Draft           
5678        Pending         
5678        Closed          
5678        Cancelled       
3333        Draft           
3333        Pending         
3333        Pending         
3333        Pending

我正在考虑使用运行计数函数（Cognos 函数）

Issue I.D   Issue Status         Running_Count

1234        Draft                1
1234        Open                 2
1234        Closed               3
5678        Draft                1
5678        Pending              2
5678        Closed               3
5678        Cancelled            4
3333        Draft                1
3333        Pending              2
3333        Pending              3
3333        Pending              4

然后使用 case 函数将结果合并到一个列中

New Concat_Column 1

case when Running_Count = 1 then Issue_status else ' ' end

New Concat_Column 2 

case when Running_Count = 2 then Issue_status else ' ' end

New Concat_Column 3 

case when Running_Count = 3 then Issue_status else ' ' end

New Concat_Column 4

case when Running_Count = 4 then Issue_status else ' ' end

然后我计划通过创建 Issue_Status_Concatenated 通过组合从 1 到

的所有新连接列来创建新数据项或新列

New Concat_Column 1 + '|' + New Concat_Column  2 + '|' + New Concat_Column 3 + '|' + New Concat_Column 4

我知道这是一个漫长的过程，但我知道可以有更简单和合乎逻辑的方法来做到这一点？有没有办法让它更简单？

Issue I.D   Issue Status   Issue_Status_Concatenated

    1234        Draft           Draft | Open | Closed
    1234        Open            Draft | Open | Closed
    1234        Closed          Draft | Open | Closed
    5678        Draft           Draft | Open | Closed |Cancelled
    5678        Pending         Draft | Open | Closed |Cancelled
    5678        Closed          Draft | Open | Closed |Cancelled
    5678        Cancelled       Draft | Open | Closed |Cancelled
    3333        Draft           Draft | Pending
    3333        Pending         Draft | Pending
    3333        Pending         Draft | Pending
    3333        Pending         Draft | Pending

Answer 1

如果其 sql 服务器其

SELECT  i.issue_id,
    stuff((
            SELECT DISTINCT ' | ' + issue_status
            FROM issues i1
            WHERE i1.issue_id = i.issue_id for xml path('')),1,3,'')
            FROM issues i

如果它是 oracle，它可能与 listagg 一致 https://docs.oracle.com/cd/E11882_01/server.112/e41084/functions089.htm#SQLRF30030

Answer 2

对于 SQL 服务器，您可以使用以下查询来获取结果 -

Create table #IssueLog (
[Issue I.D] int ,
[Issue Status] varchar(10)
)

insert into #IssueLog
select 1234 ,       'Draft'
union all  select 1234,     'Open'           
union all  select 1234,      'Closed'          
union all  select 5678,     'Draft'           
union all  select 5678,      'Pending'         
union all  select 5678,     'Closed'          
union all  select 5678,     'Cancelled'       
union all  select 3333,     'Draft'           
union all  select 3333,     'Pending'         
union all  select 3333,     'Pending'         
union all  select 3333,      'Pending'   


Select Main.[Issue I.D],
       Left(Main.[Issues],Len(Main.[Issues])-1) As [Issues]
From
    (
        Select distinct T2.[Issue I.D] ,
            (
                Select T1.[Issue Status] + '|' AS [text()]
                From #IssueLog T1
                Where T1.[Issue I.D] = T2.[Issue I.D]
                ORDER BY T1.[Issue I.D]
                For XML PATH ('')
            ) [Issues]
        From #IssueLog T2
    ) [Main]

Answer 3

下面的代码片段将帮助您在 oracle 中获得所需的输出。希望这有帮助。

SELECT ID,
  STAT,
  LISTAGG(STAT,'|') WITHIN GROUP(
ORDER BY STAT) OVER(PARTITION BY ID) AGG_STAT
FROM
  (WITH TMP AS
  ( SELECT 1234 id, 'Draft' Stat FROM dual
  UNION ALL
  SELECT 1234 ID, 'Open' STAT FROM DUAL
  UNION ALL
  SELECT 1234 id, 'Completed' Stat FROM dual
  UNION ALL
  SELECT 1100 ID, 'Draft' STAT FROM DUAL
  UNION ALL
  SELECT 1100 ID, 'Pending' STAT FROM DUAL
  UNION ALL
  SELECT 1100 ID, 'Completed' STAT FROM DUAL
  UNION ALL
  SELECT 1100 id, 'Closed' Stat FROM dual
  )
SELECT tmp.*,ROW_NUMBER() OVER(PARTITION BY ID ORDER BY 1 DESC) RN FROM tmp
  );

如果您从单个列获取数据，如何创建连接列？

How to create a concatenated column if your are getting data from a single column?

cognos

oracle11g

cognos-10