我在我的 Arduino 代码中看不到错误。

Question

这是我的代码，当我将它放入 Arduino 时 IDE 它说：

"expected primary-expression before ',' token"

我想我在某处忘记了一个点或者我在 if class.

中犯了一个小错误

非常感谢您的帮助。

代码：

#include <Servo.h>

#define trigPin 13
#define echoPin 12
#define PinOut1 

Servo myservo; 
int AnalogIn=A0;
int buttonState = 0;
int integer1 = 3;
float floating1 = PI;
String string1 = "words and numbers123";
int array1[5] = {100, 200, 300, 400, 500};
int PinIn1 = 2;
int PinOUt = 11;
int button = 0;

void setup() {
  pinMode(PinOUt, OUTPUT);
  pinMode(PinIn1, INPUT);
  Serial.begin(9600);
  myservo.attach(9);
}

void loop() {
  Conditional1();
}

void Conditional1() {
  button = digitalRead(PinIn1);
  if (buttonState == HIGH) {
    digitalwrite(PinOut1, HIGH);
    myservo.write(60);
  } else{
    digitalwrite(PinOut1, LOW);
    myservo.write(0);
  }
}

Answer 1

第 4 行说 #define PinOut1 尝试添加 space 使其成为 #define PinOut 1

编辑：在此 post 之后我还注意到了其他一些事情，所以我编译了您代码的固定版本：

#include <Servo.h>
#define trigPin 13
#define echoPin 12
#define PinOut1 11
Servo myservo; 
int AnalogIn=A0;
int buttonState = 0;
int integer1 = 3;
float floating1 = PI;
String string1 = "words and numbers123";
int array1[5] = {100, 200, 300, 400, 500};


int PinIn1 = 2;
int PinOut = 11;
int button = 0;


void setup() {
  pinMode(PinOut, OUTPUT);
  pinMode(PinIn1, INPUT);
  Serial.begin(9600);
  myservo.attach(9);
}
void loop() {
Conditional1();
}

void Conditional1() {
   button = digitalRead(PinIn1);

  if (buttonState == HIGH) {
digitalWrite(PinOut1, HIGH);
    myservo.write(60);

  } else{
    digitalWrite(PinOut1, LOW);
    myservo.write(0);

  }
}

我在我的 Arduino 代码中看不到错误。

I can't see a mistake in my Arduino code.

c

arduino

servo