为什么 PHP 输出没有显示在网页上？

Question

我没有从这个 php 代码中得到任何输出，显示空白页

 <?php
include 'conn.php';
?>
<!DOCTYPE html>
<html lang="en">
<head>
<?php include('callheadcss.php');?>
</head>
<body>

Div 显示 php 输出

<div id="slidey">
<ul>
<?php

使用准备语句

$stmt = $con->prepare('SELECT * FROM sliderimg');

$stmt->execute();
$result = $stmt->get_result();
$numRows = $result->num_rows;
if($numRows > 0)
{
while ($row = $result->fetch_assoc())
{
$imgpath=$row['SliderImg'];
echo '<li><img src="'.$imgpath.'"><p class="title">'. $row['Event_name'] .'</p><p class="description">'. $row['Eventdate'] .'</p></li>';    
}
}
?>
</ul>       
    </div>
</body>

滑块脚本

<script src="designcss/js/jquery.slidey.js"></script>
    <script src="designcss/js/jquery.dotdotdot.min.js"></script>
       <script type="text/javascript">
            $("#slidey").slidey({
                interval: 8000,
                listCount: 5,
                autoplay: false,
                showList: true
            });
            $(".slidey-list-description").dotdotdot();
        </script>

Answer 1

快速建议：

在 <body> 标签之后添加一些虚拟文本，例如 lorem ipsum：如果它没有显示，那么您的问题与您的 PHP 脚本无关
使用var_dump($numRows)确保最少使用一行

Answer 2

$stmt->execute();
$result = $stmt->get_result();
$result->store_result();
$numRows = $result->num_rows;

来自 php.net :

Returns the number of rows in the result set. The use of mysqli_stmt_num_rows() depends on whether or not you used mysqli_stmt_store_result() to buffer the entire result set in the statement handle.

If you use mysqli_stmt_store_result(), mysqli_stmt_num_rows() may be called immediately.

php.net

Answer 3

尝试使用

打印$row

print_r($row);

这将以数组格式打印 $row，这样您就可以看到所有数据是否到达

为什么 PHP 输出没有显示在网页上？

Why the PHP output is not displaying on webpage?

php

prepared-statement

ob-start