覆盖django rest generics CreateAPIView中的创建方法

Question

我的views.py django 应用程序如下，

class MemberCreate(generics.CreateAPIView):
    queryset = members.objects.all()
    serializer_class = MemberSerializer
    permission_classes = (permissions.IsAdminUser,)

    def create(self, serializer):
        ''' I wanted to do some stuff with serializer.data here '''
        pass

在上面，如果我重写创建函数，return 会失败并出现以下错误，即使我什么都不做，只是写 pass 它也会失败，

AssertionError: Expected a `Response`, `HttpResponse` or `HttpStreamingResponse` to be returned from the view, but received a `<class 'NoneType'>`

Answer 1

return 应该是 instanceof Response。您可以 return parent class 回复，在您的 stuff 之后

def create(self, request, *args, **kwargs):
    ''' I wanted to do some stuff with serializer.data here '''
    return super(MemberCreate, self).create(request, *args, **kwargs)

否则，如果您不想要父响应，则只需 return 一个 Response 实例

def create(self, request, *args, **kwargs):
    ''' I wanted to do some stuff with serializer.data here '''
    return Response(status=204)

Answer 2

您的视图应该 return 一个 Response 对象，如您的 AssertionError 堆栈跟踪中所述。

对于你的情况，你可以尝试 return 一个空的 Response 来测试你的观点和你的 serializer.data

from rest_framework.response import Response
from rest_framework import status


class MemberCreate(generics.CreateAPIView):
    queryset = members.objects.all()
    serializer_class = MemberSerializer
    permission_classes = (permissions.IsAdminUser,)

    def create(self, request, *args, **kwargs):
        serializer = self.serializer_class(...)
        data = serializer.data

        # ...

        return Response(status=status.HTTP_204_NO_CONTENT)

通常，您希望 return 您的 serializer.validated_data 最后，所以这一行可能如下所示：

return Response(serializer.validated_data, status=status.HTTP_201_CREATED)

覆盖django rest generics CreateAPIView中的创建方法

override create method in django rest generics CreateAPIView

python

django

django-generic-views

django-rest-framework