R:带多行文字的直方图副标题:如何在列中获得表格对齐方式?

R: Histogram subtitle with mtext: how to get tabular alignment in columns?

我有一个带有 multi-line 副标题的情节:

文本的当前代码:

bq1 <- bquote("Raw: "
              ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday$steps), digits=2), big.mark=","))
              ~ ", " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday$steps), digits=2), big.mark = ","))
              ~ ", median ="
              ~ .(format(median(stepsperday$steps), big.mark = ","))
)

bq2 <- bquote("Imputed: "
              ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday.imputed$steps), digits=2), big.mark=","))
              ~ ", " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday.imputed$steps), digits=2), big.mark = ",", digits = 6))
              ~ ", median ="
              ~ .(format(median(stepsperday.imputed$steps), big.mark = ","))
)

mytext <- list(bq2, bq1)
mtext(do.call(expression, mytext),side=3,line=0:1, cex=.75)

我希望 2 条线在各自的数据位上水平对齐 - 均值、sd、中位数,就像它们在 table.

中一样

有什么办法吗?

感谢任何提示,

sff

根据评论,以下内容就足够了:

data1 <- "      Raw:"
data2 <- "Imputed:"
mytext1 <- list(data2, data1)
mtext(do.call(expression, mytext1), side=3, line=0:1, adj=c(.23, .23), cex=.75)

bq1 <- bquote("  " ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday$steps), digits=2), big.mark=","))
              ~ " " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday$steps), digits=2), big.mark = ","))
              ~ " median ="
              ~ .(format(median(stepsperday$steps), big.mark = ","))
)

bq2 <- bquote("   " ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday.imputed$steps), digits=2), big.mark=","))
              ~ " " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday.imputed$steps), digits=2), big.mark = ",", digits = 6))
              ~ "   median ="
              ~ .(format(median(stepsperday.imputed$steps), big.mark = ","))
)

mytext <- list(bq2, bq1)
mtext(do.call(expression, mytext), side=3, line=0:1, adj=c(.6, .6), cex=.75)

产生输出: