如何让每个 tableView 行的 UIButton 状态不同？

Question

在这段代码中，我的按钮有 selected 状态和 deselected 状态。当按钮被按下时，它变为绿色，再次按下时它变为红色以表示 deselected 状态。

但是，所有这些都在 DetailViewController 中，当我 select 我的 tableView 中的特定行然后单击按钮显示绿色并返回并尝试不同的行时，按钮在另一行上显示绿色表示我已经按下它的行（我没有）。我想知道是否有一种方法可以只为我 select 编辑的行的 detailView 显示绿色，而为其他行显示红色？

 let defaults = UserDefaults.standard

// Outlets
@IBOutlet weak var goingButton: UIButton!

// Actions
@IBAction func goingButtonTapped(_ sender: UIButton) {

    goingButton.isSelected = !goingButton.isSelected

    if goingButton.isSelected == true {
        goingButton.setImage(UIImage(named: "goingSelected"), for: UIControlState.selected)
        defaults.set(true, forKey: "going")
        defaults.synchronize()
        defaults.bool(forKey: "going")
        print("defaults: \(defaults)")
    } else if goingButton.isSelected == false {
        goingButton.setImage(UIImage(named: "goingDeselected"), for: UIControlState.normal)
        defaults.set(false, forKey: "going")
        defaults.synchronize()
        defaults.bool(forKey: "going")

    }
}

override func viewDidLoad() {
    super.viewDidLoad()

    goingButton.setImage(UIImage(named: "goingDeselected"), for: UIControlState.normal)
    if defaults.bool(forKey: "going")
{
    goingButton.isSelected = true
    goingButton.setImage(UIImage(named: "goingSelected"), for: UIControlState.selected)

}
}

Answer 1

试试这个 -

override func viewDidLoad() {
    super.viewDidLoad()

    goingButton.setImage(UIImage(named: "goingDeselected"), for: UIControlState.normal)
    if defaults.bool(forKey: "going")
    {
        goingButton.isSelected = true
        goingButton.setImage(UIImage(named: "goingSelected"), for: UIControlState.selected)

    }
}

如何让每个 tableView 行的 UIButton 状态不同？

How can I get the UIButton state to be different for each tableView row?

ios

swift

uibutton

nsuserdefaults