通过 PHP 从 LDAP 查看 jpeg

Question

我将联系人照片存储在 openLDAP 中。一切正常，但我无法使用 PHP.

获得 base64 格式的 jpegPhoto（如 ldapsearch 输出它）

ldapsearch -x 的一部分：

*# 1486, People, domain.name
dn: uidNumber=0000,ou=People,dc=domain,dc=name
objectClass: someUnit
uidNumber: 0000
gidNumber: 0000
loginShell: /bin/false
cn:: Anon
roomNumber:: 000
telephoneNumber: 00-00-00 00-00
departmentNumber:: 000
jpegPhoto:: /9j/4AAQSkZJRgABAQEAtAC0AAD/4QzsRXhpZgAASUkqAAgAAAAIAA4BAgAgAAAAbg
 AAAA8BAgAGAAAAjgAAABABAgAPAAAAlAAAADIBAgAUAAAApAAAABMCAwABAAAAAgCaOwEQAwABAAA
 A4BAAAAIQAwABAAAAqAwAAGmHBAABAAAAuAAAAAAAAAAgICAgICAgICAgICAgICAgICAgICAgICAg
 ICAgICAgAENhbm9uAENhbm9uIElYVVMgMTMwAAAyMDExOjAyOjE3IDE0OjU3OjE5AB8AmoIFAAEAA
 AAyAgAAnYIFAAEAAAA6AgAAJ4gDAAEAAACQAc3/AJAHAAQAAAAwMjIxA5ACABQAAABCAgAABJACAB
 QAAABWAgAAAZEHAAQAAAABAgMAApEFAAEAAABqAgAAAZIKAAEAAAByAgAAApIFAAEAAAB6AgAABJI
 KAAEAAACCAgAABZIFAAEAAACKAgAAB5IDAAEAAAAFAEH/CZIDAAEAAAAYAED/CpIFAAEAAACSAgAA
 .............................................................................

PHP数据输出代码：

$ds = ldap_connect('localhost', 389)
          or die("Невозможно соединиться с $ldaphost");
$justthese = array("cn", "roomNumber", "telephoneNumber","departmentNumber","mail","jpegPhoto");
$sr=ldap_search($ds, $dn, $filter, $justthese);
$entry = ldap_get_entries($ds, $sr);
$i=0;

//Formation of the table header

..............................................................

do {

    $matches = "";

// Output "cn", "roomNumber", "telephoneNumber","departmentNumber"

    echo "<td style=\"border-right:1px solid lightgray; \" align=\"center\">".$entry[$i]["departmentnumber"][0]."</td>";
    echo "<td style=\"padding-left:20px;\"><a href=\"mailto:".$entry[$i]["mail"][0]."\">".$entry[$i]["mail"][0]."</a></td>";
    echo "</tr>";

    echo $entry[$i]["jpegphoto"][0];


    $i++;
} while ($i<count($entry)-1);
echo "</table>";

ldap_close($ds);

我想让 base64 $entry[$i]["jpegphoto"][0] 等于：“/9j/4AAQSkZJRgABAQEAtAC0AAD/4QzsRXhpZgAASUkqAAgAAAAA4BAgAAAAAbgAAAA8BAgAAAAAjgAAABABAgAPAAAAlAAAADIBAgAUAAAApAAAABMCAwABAAAAQ=16AOwE”[

但我的结果是：
"��JFIF��ExifII* n��2��;��i�� CanonCanon IXUS 1302011:02:16 10:51:57��2��:'��0221��B ��V��j�� r��z�� Y ��|��* ��0100��r^��#&��$'&��! ��! ��KH2 2011:02:16 10:51:572011:02:16 10:51:57� � =�04��"��b , �L�&1�Zbb E� " ��#��' ��(��-.��/����@�� N�� =��D�z���� IMG:IXUS 130 JPEG固件版本1.00��Q��? (p1p��@1p g ��,��F�F��Fz��?)EW��@p��@>�� ...... �� 2_b ��@��R555��R555��$��)5: F&5( ��Xh. "" $') )'$ #(,--,( .//. .//.% (,--,(# $')) '$ "" ��pc�b��q��"@u��II*��A�@p1��C ��C �� "�� }!1AQa"q2��#B��R��br� "

Answer 1

是对的，我正在获取图像的原始字节。 base64_encode-ing 输出有效：

$lil = base64_encode($entry[$i]["jpegphoto"][0]);
echo '<img src="data:image/jpeg;base64,'.$lil.'"/>';

通过 PHP 从 LDAP 查看 jpeg

Viewing jpeg from LDAP via PHP

php

encoding

ldap

base64