通过 BinarySearch 在 ArrayList 中搜索

Search in ArrayList through BinarySearch

我已经创建了 ArrayList,我想使用二进制搜索按注册号搜索狗的详细信息。我尝试使用 Collections.binarySearch 但无法弄清楚。如何使用注册号搜索狗的详细信息,例如名称和品种?

DogSort.java

public class DogSort {

    private static Scanner scanner = new Scanner(System.in);
    public static void main(String[] args) {
    ArrayList<Dog> listDog = new ArrayList<Dog>();

    listDog.add(new Dog("Max", "German Shepherd", "1001"));
    listDog.add(new Dog("Gracie","Rottweiler","1003"));
    listDog.add(new Dog("Sam", "Beagle", "1002"));

    }
}

Dog.java

class Dog {
    private String name;
    private String breed;
    private String registrationNumber;


    public Dog(String name, String breed, String registrationNumber) {
        this.name = name;
        this.breed = breed;
        this.registrationNumber = registrationNumber;
    }


    public String getName() {
        return this.name;
    }

    public String getBreed() {
        return this.breed;
    }

    public String getRegistrationNumber() {
        return this.registrationNumber;
    }

    public void setName(String name) {
        this.name = name;
    }

    public void setBreed(String breed) {
        this.breed = breed;
    }

    public void setRegistrationNumber(String registrationNumber) {
        this.registrationNumber = registrationNumber;
    }

    @Override
    public String toString() {
        return this.name;
    }

}

Collections#binarySearch() 方法接受扩展 Comparable 接口的对象列表和一个键,如果找到,returns 键在列表中的索引。您的代码的主要问题是需要使您的 Dog class 具有可比性,如下所示:

public class Dog implements Comparable<Dog> {
    private String name;
    private String breed;
    private String registrationNumber;

    public Dog(String name, String breed, String registrationNumber) {
        this.name = name;
        this.breed = breed;
        this.registrationNumber = registrationNumber;
    }

    @Override
    public int compareTo(Dog dog) {
        if (dog == null) return 1;

        if (this.registrationNumber == dog.registrationNumber) return 0;

        return this.registrationNumber > dog.registrationNumber ? 1 : -1;
    }
}

如果您继续阅读 Javadoc,您将看到:

The list must be sorted into ascending order according to the natural ordering of its elements (as by the sort(List) method) prior to making this call.

只有当您的狗列表已经按升序排序时,二分搜索才会起作用,或者至少以一种有规律的方式起作用。在这种情况下,我们已经覆盖了根据注册号排序的自然顺序。