SQL 对计数列求和以计算百分比分布的语法

Question

我正在使用 SQL Server 2014，我有以下运行良好的查询：

USE MyDatabase

SELECT [Room Nights],
       COUNT([Room Nights]) AS 'Count of RN'
FROM HOLDINGS2
GROUP BY [Room Nights]

输出结果如下：

Room Nights      Count of RN
 1                 3
 4                 10
 5                 6
 7                 25

现在我想显示另一个列，它给出 Count of RN 的百分比分布。因此，我的输出需要像这样：

Room Nights      Count of RN    % Distribution
     1                 3           6.8
     4                 10          22.7
     5                 6           13.6
     7                 25          56.8

我查看了以下讨论以尝试找出解决方案： percent distribution with counted values.

我对现有代码进行了以下修改，但它不起作用！我在 % Distribution 列中只有零。

USE MyDatabase

SELECT [Room Nights],
       COUNT([Room Nights]) AS 'Count of RN',
       CAST(COUNT([Room Nights])/(SELECT COUNT([Room Nights])*100. FROM HOLDINGS2) AS DECIMAL (9,0)) AS '% Distribution'
FROM HOLDINGS2
GROUP BY [Room Nights]

基本上，% Distribution 列应该取 Count of RN 并将其除以总计 Count of RN。

Answer 1

您可以使用 window 函数计算 % Distribution，乘以 100.0 强制结果为 float，然后将所有内容留至 1 位数逗号：

select [Room Nights]
      , count([Room Nights]) as [Count of RN]
      , cast(100.0 * count([Room Nights])/(sum(count([Room Nights])) over ()) as decimal(6,1)) as [% Distribution]
from HOLDINGS2
group by [Room Nights]

SQLFiddle

你也可以使用子查询:

select [Room Nights]
     , count([Room Nights]) as [Count of RN]
     , cast(100.0 * count([Room Nights])/(select count([Room Nights]) from HOLDINGS2) as decimal(6,1)) as [% Distribution]
from HOLDINGS2
group by [Room Nights]

SQLFiddle

Answer 2

尝试这样的事情

select [Room Nights],
       count([Room Nights]) AS 'Count of RN',
       (CONVERT(DECIMAL(9,2),count([Room Nights]))/(Select Count([Room Nights]) from HOLDINGS2))*100 as '% Distribution'
FROM HOLDINGS2
GROUP BY [Room Nights]

Answer 3

这可行：

select [Room Nights],
  count([Room Nights]) AS 'Count of RN',
  cast(
    (count([Room Nights])
    /
    (Select Count([Room Nights]) * 1.0 from HOLDINGS2) 
   ) * 100 as decimal(6,1)
  ) as '% Distribution'    
FROM HOLDINGS2
GROUP BY [Room Nights]

子查询中的* 1.0强制浮点除法，外层转换限制精度

或者，当您使用现代版本的 MSSQL 时，您可以使用 window 函数：

cast(count([Room Nights])/(sum(count([Room Nights])*1.0) over ()) * 100 as decimal(6,1))

Answer 4

尝试：

DECLARE @t TABLE
    (
      [Room Nights] INT ,
      [Count of RN] INT
    )

INSERT  INTO @t
VALUES  ( 1, 3 ),
        ( 4, 10 ),
        ( 5, 6 ),
        ( 7, 25 )


SELECT  * ,
        ROUND([Count of RN] * 100.0
              / SUM([Count of RN]) OVER ( ORDER BY ( SELECT NULL ) ), 1) AS [Percent]
FROM    @t

输出：

Room Nights Count of RN Percent
1           3           6.800000000000
4           10          22.700000000000
5           6           13.600000000000
7           25          56.800000000000

编辑：我错过了 RN 的计数是分组查询的结果。这是修改后的语句：

SELECT  [RN] ,
        COUNT(S) AS C ,
        CAST(COUNT(S) * 100.0 / SUM(COUNT(S)) OVER () AS DECIMAL(10, 1)) AS [Percent]
FROM    @t
GROUP BY [RN]

SQL 对计数列求和以计算百分比分布的语法

SQL syntax to SUM a Count column for calculating percentage distribution

sql

sql-server

count

sql-server-2014