如果带有 & 的 elif 语句给出了意外的输出

Question

我正在尝试学习 python & 在网站上尝试解决此测验时，我收到一个奇怪的错误，即第二个参数的断言失败，而 if elif 语句是正确的& 应该给出正确的输出（但它给出了错误的意外输出）

错误是：

"C:\Program Files\Python36\python.exe" C:/Users/.../PycharmProjects/pythonSnakegame/snakeGame.py
Fizz Buzz
Traceback (most recent call last):
Fizz Buzz
  File "C:/Users/..../PycharmProjects/pythonSnakegame/snakeGame.py", line 28, in <module>
    assert checkio(6) == "Fizz", "6 is divisible by 3"
AssertionError: 6 is divisible by 3

Process finished with exit code 1

def checkio(number):
    # Your code here
    # It's main function. Don't remove this function
    # It's using for auto-testing and must return a result for check.
    if number % 3 == 0 & number % 5 == 0:
        result = "Fizz Buzz"
    elif number % 3 == 0:
        result = "Fizz"
    elif number % 5 == 0:
        result = "Buzz"

    # replace this for solution
    print (result)
    return result
    # return str(number)


# Some hints:
# Convert a number in the string with str(n)

# These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
    assert checkio(6) == "Fizz", "6 is divisible by 3"
    assert checkio(5) == "Buzz", "5 is divisible by 5"
    assert checkio(7) == "7", "7 is not divisible by 3 or 5"
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

感谢您的帮助

Answer 1

&运算符用于二进制操作，您应该使用and（布尔值运算符） .

I kept wondering why it was not working

& 正在禁用 5 的模块操作检查，所以在得到 True 的地方基本上都可以被 3 整除，检查这个输出测试：

number = 12
number % 3 == 0 & number % 5 == 0
True

如果带有 & 的 elif 语句给出了意外的输出

if elif statement with & is giving unexpected output

python

if-statement

fizzbuzz