class stdClass 的对象无法转换为 SOAP 请求的字符串

Question

当我运行以下脚本时，出现“ class stdClass 的对象无法转换为 SOAP 请求 的字符串”错误$client->LatLonListZipCode($args) 行，我不知道为什么。有什么想法吗？

<?php
$contextOptions = array(
            'ssl' => array(
                'verify_peer'   => false,
                'verify_peer_name' => false,
                'allow_self_signed' => true
            ),
            'http' => array(
                'timeout' => 5 //seconds
            )
 );

//create stream context
$stream_context = stream_context_create($contextOptions);

//create client instance (over HTTPS)
$client = new SoapClient('http://graphical.weather.gov/xml/DWMLgen/wsdl/ndfdXML.wsdl', array(
            'cache_wsdl'  => WSDL_CACHE_NONE,
            'exceptions' => 1,
            'trace' => 1,
            'stream_context' => $stream_context,
            'soap_version'=> SOAP_1_2,
            'connection_timeout' => 5 //seconds
));//SoapClient

$args = new stdClass();
$args->zipCodeList = '10001';

$z = $client->LatLonListZipCode($args);

Answer 1

异常原因

首先 - 此服务使用 SOAP 1.1 不 SOAP 1.2。将您的 $client 规格更改为：

$client = new SoapClient('http://graphical.weather.gov/xml/DWMLgen/wsdl/ndfdXML.wsdl', array(
            'cache_wsdl'  => WSDL_CACHE_NONE,
            'exceptions' => 1,
            'trace' => 1,
            'stream_context' => $stream_context,
            'soap_version'=> SOAP_1_1,//<-- note change here
            'connection_timeout' => 5 //seconds
));//SoapClient

服务定义

如您的WSDL service specification所述，您可以发现LatLonListZipCode函数定义为：

<operation name="LatLonListZipCode">
    <documentation>Returns a list of latitude and longitude pairs with each pair corresponding to an input zip code.</documentation>
    <input  message="tns:LatLonListZipCodeRequest"/>
    <output message="tns:LatLonListZipCodeResponse"/>
</operation>

预期参数定义为：

<xsd:simpleType name="zipCodeListType">
    <xsd:restriction base='xsd:string'>
        <xsd:pattern value="\d{5}(\-\d{4})?( \d{5}(\-\d{4})?)*" />
    </xsd:restriction>
</xsd:simpleType>

正确调用

所以我们知道，服务器只需要一个名为 zipCodeList 的 string 参数。现在我们可以推断出你的代码应该是这样的：

$args = array("zipCodeList"=>'10001');
try {
$z = $client->LatLonListZipCode($args);
} catch (SoapFault $e) {
    echo $e->faultcode;
}

请注意，我正在捕获 SoapFault 异常。它将帮助您了解服务器端错误。在 PHP documentation.

中阅读更多相关信息

class stdClass 的对象无法转换为 SOAP 请求的字符串

Object of class stdClass could not be converted to string for SOAP request

php

soap

wsdl

异常原因

服务定义

正确调用