仅按顺序的日期范围分组

Question

我正在尝试生成日期范围序列，如果排序中断，则将日期放在第二行。

fldDate        TotalNo
2015-04-01     10
2015-04-02     10
2015-04-03     10
2015-04-04     10
2015-04-05     10
2015-04-06     10
2015-04-07     10
2015-04-08     10
2015-04-09     12
2015-04-10     12
2015-04-11     12
2015-04-12     12
2015-04-20     12
2015-04-21     12
2015-04-22     12
2015-04-23     12
2015-04-24     12
2015-04-25     12

我真的很难过

我想要这个table作为

StartDate      EndDate      TotalNo
2015-04-01     2015-04-08   10
2015-04-09     2015-04-12   12
2015-04-20     2015-04-25   12

表示日期范围中断或 TotalNo change 它应该创建一个新行。

我已经做到了，但还没有完全奏效我在做

SELECT MIN(fldDate) AS StartDate,
       MAX(fldDate) AS EndDate,
       TotalNo
FROM dbo.tbl1
GROUP BY TotalNo
ORDER BY fldDate

它将创建像

StartDate      EndDate      TotalNo
2015-04-01     2015-04-08   10
2015-04-09     2015-04-25   12

Answer 1

您可以通过从 fldDate 中减去一个整数序列来识别组——例如 row_number() 提供的。减法后连续的日期将具有相同的值。剩下的只是 group by:

select min(fldDate) as StartDate, max(fldDate) as EndDate, TotalNo
from (select t.*,
             dateadd(day,
                     - row_number() over (partition by TotalNo order by fldDate),
                     fldDate) as grp
      from table t
     ) t
group by TotalNo, grp
order by StartDate, TotalNo;

仅按顺序的日期范围分组

Group By Date Range of Sequenced Only

sql

sql-server

group-by

date-range