XSLT 1.0 中的序列编号

Question

您好，在 XSLT 格式方面需要一些帮助，以便为 元素标签 创建序列号。大多数情况下 Element tag 会遗漏一些序列中的数字，我需要通过将缺失的数字添加到 Element tag 中以如下所示的顺序格式获得输出座位标签的相同序列。

非常感谢在此方面的任何帮助，在此先感谢。

输入

<book>
<Seat>
    <seatNumber>12A</seatNumber>
    <Element>1</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12B</seatNumber>
    <Element>3</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12C</seatNumber>
    <Element>4</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12D</seatNumber>
    <Element>5</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12E</seatNumber>
    <Element>7</Element>
    <Number>1</Number>
</Seat>
</book>

输出

<book>
<Seat>
    <seatNumber>12A</seatNumber>
    <Element>1</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12B</seatNumber>
    <Element>2</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12C</seatNumber>
    <Element>3</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12D</seatNumber>
    <Element>4</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12E</seatNumber>
    <Element>5</Element>
    <Number>1</Number>
</Seat>
</book>

Answer 1

这样试试：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="Element">
    <xsl:copy>
        <xsl:number count="Seat"/>
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>

XSLT 1.0 中的序列编号

Sequence numbering in XSLT 1.0

xslt

xslt-1.0

xslt-grouping