Select 具有不同最大值（列值）的行

Question

[ExactReplica].[FilteredOpportunityProduct] Table

Opportunityid      baseamount
1                  500
1                  500
2                  600
2                  700

[ExactReplica].FilteredOpportunity Table

Opportunityid   name
1                ABC
2                CDF

我要取最大基数；但是，当存在重复的 baseamount 时，我会遇到问题，我怎样才能只记录一条记录

我的查询

  select
     MaxAmount.[baseamount] ,
     c.name


 FROM [ExactReplica].FilteredOpportunity c

 Left JOIN
        (
            SELECT  opportunityid,
                    MAX((baseamount)) baseamount
            FROM    [ExactReplica].[FilteredOpportunityProduct] 
            GROUP BY   opportunityid

        ) MaxAmount ON c.opportunityid = MaxAmount.opportunityid
    inner JOIN
        [ExactReplica].[FilteredOpportunityProduct]  p ON   MaxAmount.opportunityid = p.opportunityid
                    AND MaxAmount.baseamount = p.baseamount

Answer 1

试试这个：

select max(baseamount) baseamount,a.name
from
(select
     baseamount, ROW_NUMBER() over (partition by p.opportunityid,baseamount order by p.baseamount desc) rn,
     c.name

 FROM FilteredOpportunity c
    inner JOIN
        [FilteredOpportunityProduct]  p ON   c.opportunityid = p.opportunityid) a
        where rn=1
        group by a.name

输出：

baseamount  name
500         ABC
700         CDF

Answer 2

您可以尝试以下查询以获得预期结果吗，我已经执行了以下脚本：

对于Table创作：

创建 TABLE FILTEREDOPPORTUNITYPRODUCT ( 机会 ID INT NULL， BASEAMOUNT VARCHAR(24) 空值 )

创建 TABLE 过滤机会（机会 ID INT NULL，名称 VARCHAR(24) NULL )

插入：

插入 FILTEREDOPPORTUNITYPRODUCT (OPPORTUNITYID,BASEAMOUNT) 值 (1,500),(1,500),(2,600),(2,700)

插入已过滤的机会（机会 ID，名称）值 (1,'ABC'),(2,'CDF')

选择：

SELECT A.OPPORTUNITYID,B.NAME,MAX(BASEAMOUNT) 作为 BASEAMOUNT FROM FILTEREDOPPORTUNITYPRODUCT AS
以 B
身份加入筛选机会 ON A.OPPORTUNITYID = B.OPPORTUNITYID 按 A.OPPORTUNITYID、B.NAME

分组

Select 具有不同最大值（列值）的行

Select row with Distinct max(column value)

sql-server

sql-server-2012

ssms-2012

对于Table创作：

插入：

选择：