Phonegap 在应用程序处于前台时管理通知

Question

我正在使用 cordova 和 phonegap 构建移动应用程序。当通知 reaches.Is 在 cordova 中有任何插件时，我想在设备屏幕上显示一个弹出窗口。

Answer 1

来自https://programmingistheway.wordpress.com/2017/07/19/devextremephonegap-how-to-manage-push-notifications-with-fcm/

注册、通知和错误这3个事件只有在应用打开时才会被管理。

Registration: the APP registers itself to the push service, receiving a unique registrationId. This event is useful if you want to store this value to send notifications to single devices;

Notification: instead of show the classic notification pop up (depending on the phone), the event notication shows a little pop up (using DevExtreme feature) to read the message, if the APP is open (if the app is closed, you will get the notification in the classic way);

Error: if the APP is open and the notification throws some error, here you can manage it.

因此，您必须管理的事件是通知。当应用程序在前台发送通知时会引发此事件（因此，当应用程序运行）。

在 deviceReady 事件中插入此代码：

var push = PushNotification.init({
    android: {
    },
    ios: {
        alert: "true",
        badge: "true",
        sound: "true",
        clearBadge: "true"
    },
    windows: {}
});
push.on('registration', function (data) {
    // data.registrationId
    DevExpress.ui.notify("Device registered " + data.registrationId, "success", 3000);
});
push.on('notification', function (data) {
    // data.message,
    // data.title,
    // data.count,
    // data.sound,
    // data.image,
    // data.additionalData
    // mostra la notifica se l'app è aperta
    DevExpress.ui.notify(data.message, "info", 10000);
});
push.on('error', function (e) {
    // e.message
    // sarà da togliere, utilissimo in fase di debug
    DevExpress.ui.notify(e.message, "error", 10000);
});

并在通知事件中插入您需要的代码。在这种情况下，使用了 DevExtreme，但如果你不使用它，你可以只显示一个 alert or look for what you need (example)enter link description here.

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