如何计算成功查找（和替换）

Question

我正在尝试计算像这样的简单脚本所做的替换次数：

$count = 0
Function findAndReplace($objFind, $FindText, $ReplaceWith) {
    $count += $objFind.Execute($FindText, $matchCase, $matchWholeWord, \`
             $matchWildCards, $matchSoundsLike, $matchAllWordForms, \`
             $forward, $findWrap, $format, $ReplaceWith, $replace)
}

替换完成，但 $count 仍为 0...

Answer 1

$count 必须在要使用的函数内部或将其作为参数。

试试这个

Function findAndReplace($objFind, $FindText, $ReplaceWith) {
    $count = 0
    $replacementfound = $objFind.Execute($FindText, $matchCase, $matchWholeWord, \`
             $matchWildCards, $matchSoundsLike, $matchAllWordForms, \`
             $forward, $findWrap, $format, $ReplaceWith, $replace)

    if ($replacementfound -eq "True"){$count++}
    write-host $count
}

Answer 2

This is a scoping issue. AFAIK $count不用先初始化

增量逻辑看起来找到了。但是，您需要在增量后从函数中 return 它。否则它仍将是 0 在函数外的范围内定义的。

Function findAndReplace($objFind, $FindText, $ReplaceWith) {
    $count += $objFind.Execute($FindText, $matchCase, $matchWholeWord, \`
             $matchWildCards, $matchSoundsLike, $matchAllWordForms, \`
             $forward, $findWrap, $format, $ReplaceWith, $replace)
    return $count;
}

$myCountOutSideFunctionScope = findAndReplace -objFind ... -FindText ... -ReplaceWith ...

如何计算成功查找（和替换）

How to count successful find (and replace)

powershell

counter

find-replace