MySQL 中的自然排序尝试失败

Question

我试图在 MySQL 中实现 natural/alphanumeric 排序，但没有成功。我已经阅读了几篇 Stack 文章和关于我在 google 搜索中找到的主题的各种文章。这是我开始的基本查询：

select VideoTitle, VideoID from Filters where VideoSource = 'Netflix' and IMDBSeries = 'tt0367279' and PublishDate is not null ORDER BY VideoTitle

该查询产生此结果集：

Arrested Development Season 1: Ep. 1 Pilot Arrested Development Season 1: Ep. 10 Pier Pressure Arrested Development Season 1: Ep. 2 Top Banana Arrested Development Season 1: Ep. 3 Bringing Up Buster Arrested Development Season 1: Ep. 4 Key Decisions Arrested Development Season 1: Ep. 5 Charity Drive Arrested Development Season 1: Ep. 6 Visiting Ours Arrested Development Season 1: Ep. 7 In God We Trust Arrested Development Season 1: Ep. 8 My Mother, the Car Arrested Development Season 1: Ep. 9 Storming the Castle

请注意，从自然排序的角度来看，此行是乱序的：

Arrested Development Season 1: Ep. 10 Pier Pressure

基于我阅读的 posts/articles，我也尝试了这些方法及其附带的结果集：

select VideoTitle from Filters where VideoSource = 'Netflix' and IMDBSeries = 'tt0367279' and PublishDate is not null ORDER BY CAST(VideoTitle AS UNSIGNED), VideoTitle

Arrested Development Season 1: Ep. 1 Pilot Arrested Development Season 1: Ep. 10 Pier Pressure Arrested Development Season 1: Ep. 2 Top Banana Arrested Development Season 1: Ep. 3 Bringing Up Buster Arrested Development Season 1: Ep. 4 Key Decisions Arrested Development Season 1: Ep. 5 Charity Drive Arrested Development Season 1: Ep. 6 Visiting Ours Arrested Development Season 1: Ep. 7 In God We Trust Arrested Development Season 1: Ep. 8 My Mother, the Car Arrested Development Season 1: Ep. 9 Storming the Castle

select VideoTitle from Filters where VideoSource = 'Netflix' and IMDBSeries = 'tt0367279' and PublishDate is not null ORDER BY LENGTH(VideoTitle), VideoTitle

Arrested Development Season 1: Ep. 1 Pilot Arrested Development Season 1: Ep. 2 Top Banana Arrested Development Season 1: Ep. 4 Key Decisions Arrested Development Season 1: Ep. 5 Charity Drive Arrested Development Season 1: Ep. 6 Visiting Ours Arrested Development Season 1: Ep. 10 Pier Pressure Arrested Development Season 1: Ep. 7 In God We Trust Arrested Development Season 1: Ep. 3 Bringing Up Buster Arrested Development Season 1: Ep. 8 My Mother, the Car Arrested Development Season 1: Ep. 9 Storming the Castle

select VideoTitle from Filters where VideoSource = 'Netflix' and IMDBSeries = 'tt0367279' and PublishDate is not null ORDER BY VideoTitle + 0 ASC

Arrested Development Season 1: Ep. 1 Pilot Arrested Development Season 1: Ep. 9 Storming the Castle Arrested Development Season 1: Ep. 8 My Mother, the Car Arrested Development Season 1: Ep. 7 In God We Trust Arrested Development Season 1: Ep. 6 Visiting Ours Arrested Development Season 1: Ep. 5 Charity Drive Arrested Development Season 1: Ep. 4 Key Decisions Arrested Development Season 1: Ep. 3 Bringing Up Buster Arrested Development Season 1: Ep. 2 Top Banana Arrested Development Season 1: Ep. 10 Pier Pressure

有什么想法吗？

Answer 1

如果你真的想要，你可以逐条排序：

order by substring_index(VideoTitle, ' Season ', 1),
         substring_index(VideoTitle, ' Season ', -1) + 0,
         substring_index(VideoTitle, ': Ep. ', -1) + 0

这假设字符串 ' Season ' 和 : Ep. 在每个标题中只出现一次。

下面的版本应该也很接近，假设季节只有一个数字：

order by substring_index(VideoTitle, ': Ep. ', 1),
         substring_index(VideoTitle, ': Ep. ', -1) + 0

Answer 2

最好的解决方案是将节目标题、剧季、剧集编号和剧集标题存储在单独的列中。

在这种情况下，您可以进行一些字符串操作来获得所需内容。

ORDER BY SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(VideoTitle, ': ', -1), ' ', 2), ' ', -1)+0

不过，这是一个非常脆弱的解决方案。

Answer 3

如果创建新列以使您的模型更易于搜索，我会采用更优雅的解决方案，而不是逐个分解字符串。

select VideoTitle 
  from (select VideoTitle, 
               VideoTitle REGEXP '.+Ep\. [0-9]{2}.+' vd2dig 
          from videos
       ) sub
 order by vd2dig, VideoTitle;

这基本上会使 VideoTitle 有两位数字时变为 1，而当它有一位数字时它将是 0 所以我先按此列排序，然后按自然顺序排序VideoTitle

看到它在这里工作：http://sqlfiddle.com/#!9/6abde/1

MySQL 中的自然排序尝试失败

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