如何在 ModelView 中添加另一个值并从我的 Action 中传递它

Question

在我的产品部分视图中 table

@model IEnumerable<Products.Models.ProductModelView>

如果用户 departmentId 与产品 departmentId 不同，我正在尝试（隐藏）不显示某些按钮

<table class="table table-responsive table-hover table-striped">
    <tr>
        <th>Product type</th>
        <th></th>
    </tr>

    @foreach (var item in Model)
    {
        <tr>
            <td>
                @Html.DisplayFor(modelItem => item.ProductName)
            </td>

            //  I want to hide if current inlogged userDepartmentId is not the same as product departmentId
            // Like @if(@item.ProductDeptId == userDepartmentId) {
            <td>
                <Button class="btn btn-success glyphicon btn-xs glyphicon-plus" onclick="return EditDelete(@(item.ProductId) )">Edit/Delete</Button>&nbsp;
            </td>
            }
        </tr>
    }

这是我的 Class，我正在尝试创建但不知道如何传递到我的 PartielView

的 ViewModel 和 Action

 public class Product
 {
     public int ProductId { get; set; }
     public string productName { get; set; }
     public int DepartmentId { get; set; }
 }

public class ProductModelView
{
    public int ProductId { get; set; }
    public string productName { get; set; }
    public int DepartmentId { get; set; }
    public int UserDepartmentId { get; set; }
}

[HttpGet]
public ActionResult Lager()
{
    using (context)
    {
        string user = User.Identity.Name;
        int deptId = context.Users.Where(u => u.UserName == user).Select(d => d.DepartmentId).SingleOrDefault();

        // Here I don't know how to continue ... I try like this
        Product pr = new Product();
        ProductModelView prModel = new ProductModelView();
        prModel.ProductId = pr.ProductId;
        prModel.productName  = pr.productName ;
        prModel.DepartmentId= pr.DepartmentId;
        prModel.UserDepartmentId = DeptId;

        // And then, how to return and what to return?

        return PartialView("_ProductList",  prModel); // Is this right? Returning prModel?
    }

谁能帮我制定 Class、ViewModel 和 Action？

Answer 1

创建一个 "composite" 对象并传递它（根据@Uwe）：

public class ProductListViewModel
{
    public IEnumerable<ProductModelView> Products { get; set; }
}

并相应地更改 @model：

@model ProductListViewModel

或构造并传递IEnumerable<ProductModelView> products给return PertialView():

// IQueryable<Product>
var products = from p in context.Products
               where p.DepartmentId == depId // aware! would cause 2 queries to db, shall be rewritten
               select p;
var prModels = from p in products.AsEnumerable() // 'memorize' db query into in-memory objects
               select new ProductViewModel
               {
                   ProductId = p.ProductId,
                   ProductName = p.productName,
                   DepartmentId = p.DepartmentId;
                   UserDepartmentId = deptId;
               };
return return PartialView("_ProductList", prModels);

如何重写：

要么配置一个导航属性（推荐）：

public class Product
{
    public User { get; set; }
}

或执行直接连接：

var products = from p in context.Products
               join u in context.User on p.UserDepartmentId = u.UserDepartmentId // or whatever it is
               where u.UserName == userName // it's better to use userId which is likely the primary key
               select p;

如何在 ModelView 中添加另一个值并从我的 Action 中传递它

How can I add another value in ModelView and pass it from my Action

c#

asp.net

asp.net-mvc

entity-framework

asp.net-mvc-4