JPA 2.0 CriteriaBuilder：SELECT 来自...

Question

我想使用 JPA 2.0 CriteriaBuilder 创建以下 SQL 查询：

SELECT * FROM PROFIL WHERE PROFILID IN (SELECT PROFILID FROM ROLEPROFIL WHERE ROLEID = roleId)

这是我的类 :

简介：

public class Profil extends AbstractDomain<Long> {

    @Id
    @Column
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "idgen_x")
    @UiInfo(name = "Identifiant")
    private Long profilId;

    @Column(nullable = false)
    @UiInfo(name = "Libellé")
    private String lib;

}

作用：

public class Role extends AbstractDomain<Long> {
    @Id
    @Column
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "idgen_x")
    @UiInfo(name = "Identifiant")
    private Long roleId;
}

角色简介：

public class RoleProfil extends AbstractDomain<Long> {
    @Id
    @Column
    @UiInfo(name = "Identifiant")
    private Long roleProfilId;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(nullable = false)
    @UiInfo(name = "Profil")
    private Profil profilId;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(nullable = false)
    @UiInfo(name = "Rôle")
    private Role roleId;

}

我想做的是创建一个函数，使用 JPA 通过 Role ID 获取 Profils。

这是我开始的，但我是 JPA 的新手，我不知道该怎么做：

public List<Profil> findProfilsByRoleId(Long roleId) {
        final CriteriaBuilder builder = getCriteriaBuilder();
        final CriteriaQuery<Profil> criteriaQuery = builder.createQuery(Profil.class);
        final Root<Profil> from = criteriaQuery.from(Profil.class);

        //TODO

        TypedQuery<Profil> query = getEntityManager().createQuery(criteriaQuery);
        return query.getResultList();

    }

我该怎么做？

Answer 1

SELECT  PF.* 
FROM PROFIL AS PF
INNER JOIN ROLEPROFIL AS RPF
ON RPF.PROFILID = PF.PROFILID 
WHERE RPF.ROLEID = {roleId}

可能是更容易实现的查询。我认为 java 中的代码可能是这样的（我还没有测试刚刚提出的解决方案）：

public List<Profil> findProfilsByRoleId(Long roleId) {
    final CriteriaBuilder builder = getCriteriaBuilder();
    final CriteriaQuery<Profil> query = builder.createQuery(Profil.class);
    final Root<RoleProfil> from = query.from(RoleProfil.class);

    query.select(from.get(RoleProfil_.profilId));
    query.where(builder.equal(from.get(RoleProfil_.roleId).get(Role_.roleId), roleId));

    final TypedQuery<Profil> typedQuery = getEntityManager().createQuery(query);
    return typedQuery.getResultList();

}

JPA 2.0 CriteriaBuilder：SELECT 来自...

JPA 2.0 CriteriaBuilder : SELECT FROM … IN

java

jpa

criteria

jpa-2.0