无法通过 wmic 启动 npm

Question

如果我放入 bat 文件命令来启动 node

wmic process call create "npm run go","%~dp0."

一切正常：

D:\Temp\Supertemp\wmic npm>wmic process call create "node go","D:\Temp\Supertemp\wmic npm\."
Идет выполнение (Win32_Process)->Create()
Метод успешно вызван.
Параметры вывода:
instance of __PARAMETERS
{
        ProcessId = 13292;
        ReturnValue = 0;
};

但是如果我改用npm

wmic process call create "npm run go","%~dp0."

出现错误9，according to msdn msdn表示找不到路径：

D:\Temp\Supertemp\wmic npm>wmic process call create "npm run go","D:\Temp\Supertemp\wmic npm\."
Идет выполнение (Win32_Process)->Create()
Метод успешно вызван.
Параметры вывода:
instance of __PARAMETERS
{
        ReturnValue = 9;
};

文件package.json:

{
  "name": "wmic-npm-test",
  "version": "0.0.0",
  "scripts": {
    "go": "node go"
  }
}

文件go.js:

setInterval(function () {
  console.log(require('process').cwd());
}, 1000);

如果只是从控制台启动 npm，一切正常：

D:\Temp\Supertemp\wmic npm>npm run go

> wmic-npm-test@0.0.0 go D:\Temp\Supertemp\wmic npm
> node go

D:\Temp\Supertemp\wmic npm
D:\Temp\Supertemp\wmic npm

我通过 wmic to get process id.

启动它

PS: Same question in Russian.

Answer 1

像这样尝试（我在问题下的评论中的模式详细信息）：

@echo off

for %%a in (npm.cmd) do set "npm_path=%%~f$PATH:a"
echo %npm_path%

wmic process call create "cmd.exe /c call \"%npm_path%\" ","%~dp0."

Answer 2

npm.cmd 和 npm 文件 sh:

D:\Temp\Supertemp\wmic npm>where npm
C:\Program Files\nodejs\npm
C:\Program Files\nodejs\npm.cmd

要执行 npm 命令，您需要指定要运行 cmd-file:

wmic process call create "npm.cmd run go","%~dp0."

无法通过 wmic 启动 npm

Can't start npm via wmic

windows

batch-file

npm

wmic