如何对 T10=] 中的 time(7) 数据类型求和？

Question

如何在t-sql中求和两次数据类型？

 declare @fTime time(7)='05:22';
 declare @tTime time(7)='06:00';
 declare @result time(7);

我用了这个但是没用。

set  @result=sum(@fTime+@tTime);

Answer 1

你能用这样的东西吗？

DECLARE @fTime TIME(7) = '05:22';
DECLARE @tTime TIME(7) = '06:00';
DECLARE @result TIME(7);

SELECT @result = CAST([Hours] AS NVARCHAR) + ':' + CAST([Minutes] AS 
NVARCHAR)
FROM (
SELECT cast(TotalTime AS INT) / 60 AS [Hours]
    ,CAST(TotalTime AS INT) % 60 AS [Minutes]
FROM (
    SELECT fTime + tTime AS TotalTime
    FROM (
        SELECT cast(SUBSTRING(cast(@ftime AS NVARCHAR), 1, 2) AS INT) * 60 + 
CAST(substring(cast(@ftime AS NVARCHAR), 4, 2) AS INT) AS fTime
            ,cast(SUBSTRING(cast(@tTime AS NVARCHAR), 1, 2) AS INT) * 60 + 
CAST(substring(cast(@tTime AS NVARCHAR), 4, 2) AS INT) AS tTime
        ) x
    ) y
) z

SELECT @result

Answer 2

您可以像这样将一个的分钟数加到另一个：

select dateadd(minute,datediff(minute,'00:00',@tTime),@fTime)

但是，请注意 dlatikay 的评论是正确的，time(7) 并不意味着持续时间。最好将持续时间存储为整数，例如存储分钟或秒。

如何对 T10=] 中的 time(7) 数据类型求和？

How to sum time(7) data types in T-SQL?

tsql

datetime

timespan