JSON 正在解析 Objective-c[xcode 6]

Question

我收到这样的回复。我怎样才能得到这些值？ MODEOFTRAVEL_ID 这是键值，MODEOFTRAVELNAME 这是另一个键。

{
        ColumnValuesList =         (
                        (
                1,
                Flight
            ),
                        (
                2,
                Train
            ),
                        (
                3,
                "By Road"
            ),
                        (
                21,
                "By Bus"
            )
        );
        TableColumns =         (
            "MODEOFTRAVEL_ID",
            MODEOFTRAVELNAME
        );
        TableName = "CTZ_MODEOFTRAVEL";
    },

Answer 1

如果问题数据是 NSDictionary 变量（比如 d）的内容，则：

示例：

NSDictionary *d = @{
    @"ColumnValuesList" : @[
        @[ @1,  @"Flight" ],
        @[ @2,  @"Train" ],
        @[ @3,  @"By Road" ],
        @[ @21, @"By Bus" ]
    ],
    @"TableColumns" : @[
        @"MODEOFTRAVEL_ID",
        @"MODEOFTRAVELNAME"
    ],
    @"TableName" : @"CTZ_MODEOFTRAVEL"
    };

NSString *columnName0 = d[@"TableColumns"][0];
NSString *columnName1 = d[@"TableColumns"][1];
NSLog(@"columnName0: %@", columnName0);
NSLog(@"columnName1: %@", columnName1);

输出：

columnName0: MODEOFTRAVEL_ID
columnName1: MODEOFTRAVELNAME

JSON 正在解析 Objective-c[xcode 6]

JSON Parsing in Objective-c[xcode 6]

objective-c

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json

xcode6.1