方法 getline c++ 后 Switch 语句反应错误

Question

我正在为大学编写一个银行应用程序，我偶然发现了一个问题。让我们以我的 class 客户的方法为例。

void Customer::create_customer_data() {
    cout << "Client' Address: ";
    getline(cin, clientAddress);
    cin.ignore();
    cout << "Client's birth date: ";
    getline(cin, clientBirthDate);
    cin.ignore();
    cout << "Client's telephone number: ";
    getline(cin, clientTelephoneNumber);
    cin.ignore();
    cin.clear(); }

在主函数中，我有一个处理用户选择的 switch 语句。

int main() {
int choice, _globalClientNumber = 0;
Customer a(_globalClientNumber);
cout << "Welcome to bank manager 1.0!" << endl;

do {
    cout << "Main Menu"<< endl;
    cout << "Create a new customer (1)" << endl;
    cout << "Create a new account (2)" << endl;
    cout << "Cash money into account (3)" << endl;
    cout << "Cash money out of account (4)" << endl;
    cout << "Transfer money between two accounts (5)" << endl;
    cout << "See current status of a customer and its accounts (6)" << endl;
    cout << "End Application (0)" << endl;

    cout << "Choice: ";
    cin >> choice;

    switch (choice) {
        case 1:
            a.create_customer_data();
            break;
        case 2:
            a.create_new_account();
            break;
        case 3:
            a.cash_in();
            break;
        case 4:
            a.cash_out();
            break;
        case 5:
            a.transfer_money();
            break;
        case 6:
            a.print();
            break;
        default:
            break;
    }

    cout << endl;
}
while (choice != 0);

return 0; }

我一直遇到的问题是，通过 create_customer_data 方法在屏幕上写入的值正在由 do-while 循环处理。因此，如果 create_customer_data 中的 clientTelephoneNumber 不以 0 结尾，则主菜单会通过 do-while 循环显示两次。如果有人能告诉我我的错误在哪里，我将不胜感激。

编辑：简而言之：choice 变量被覆盖并且 do-while 循环再次执行，导致重复打印菜单。

Answer 1

我会说，你的 cin 需要冲洗。

可以在这里找到答案： How do I flush the cin buffer?

方法 getline c++ 后 Switch 语句反应错误

Switch statemement reacting wrong after method getline c++

c++

methods

class

switch-statement

do-while