初学者编码挑战的麻烦

Question

编写一个程序，持续要求用户输入 5 以外的任何数字，直到用户输入数字 5。然后告诉用户"Hey! you weren't supposed to enter 5!"并退出程序。

★ 修改程序，迭代10次后，如果用户还没有输入5，则告诉用户"Wow, you're more patient then I am, you win."并退出。

★★ 修改程序，使其要求用户输入任何数字，而不是与他们被要求输入数字的次数相等的数字。（即在第一次迭代 "Please enter any number other than 0" 和第二次迭代 "Please enter any number other than 1"m 等。当用户输入他们被要求不要输入的数字时，程序必须相应地退出。）

我的大部分程序都可以运行。我已经达到了这样的程度，它要求一个从 0 开始并上升的数字，它在 10 次尝试后向用户提供耐心的消息，如果他们输入了他们不应该输入的数字，则退出程序。但是，如果用户输入的数字高于它告诉您不要输入的数字，则程序退出时不会显示任何消息。

我真的不知道要搜索什么来解决这个问题。然而，我已经尝试移动一些东西，并摆脱了一些冗余变量。

任何提示将不胜感激，请不要预先给我答案！这是我目前所拥有的。

#include <iostream>


int main()
{
    const int GUESS = 1; // constant for number of tries
    const int PATIENCE = 10; // constant for message at 10 tries
    int UserNum; // player input
    int InputNum = GUESS; // intializes GuessNumber


    // asks for player input
    do
    {
        std::cout << "Enter any number other then "<< InputNum << ": ";
        std::cin >> UserNum;

        // exits program if user inputs the number displayed
        if (UserNum == InputNum)
        {
            std::cout << "Hey! you weren't supposed to enter " << InputNum << "!\n";
        }
        // increase the Guess counter if they dont enter the number displayed
        else if (UserNum != InputNum)
        {
            InputNum++;

        }

        if (InputNum == PATIENCE)
        {
            std::cout << "Wow, you're more patient then I am, you win.\n";
            break;
        }
    } while (UserNum != InputNum);



    return 0;
}

Answer 1

你的问题在do while循环条件

首先执行语句，然后检查条件

例如

InputNum初始化为1

所以如果您输入 2 作为 UserNum 的输入，在 else if 条件下，InputNum 将增加到 2

评估此条件时

 while (UserNum != InputNum)

它将是错误的，因为 2==2

循环中断

解决方案

更改 PATIENCE = 11 并使用

while (1)   
// this will run infinitely but it will break after 10 iteration or when u press the same number which u shouldn't

而不是

while (UserNum != InputNum)

完整程序

#include <iostream>


int main()
{
    const int GUESS = 1; // constant for number of tries
    const int PATIENCE = 11; // constant for message at 10 tries
    int UserNum; // player input
    int InputNum = GUESS; // intializes GuessNumber


                          // asks for player input
    do
    {
        std::cout << "Enter any number other then " << InputNum << ": ";
        std::cin >> UserNum;

        // exits program if user inputs the number displayed
        if (UserNum == InputNum)
        {
            std::cout << "Hey! you weren't supposed to enter " << InputNum << "!\n";
            break;
        }
        // increase the Guess counter if they dont enter the number displayed
        else if (UserNum != InputNum)
        {
            InputNum++;

        }

        if (InputNum == PATIENCE)
        {
            std::cout << "Wow, you're more patient then I am, you win.\n";
            break;
        }
    } while (1);


    system("pause");
    return 0;
}

Answer 2

嘿，试试这个程序，它完全符合您的要求。

 #include <iostream>
    int main ()
    {
      int GUESS = -1;       //loop variable
      const int PATIENCE = 10;  // constant for message at 10 tries
      int InputNum;         // input from user



  std::cout << "PATIENCE Test" << "!\n";


  do
    {
      GUESS++;
      // asks for player's input
      std::cout << "Enter any number other than " << GUESS << ": ";
      std::cin >> InputNum;

      // exits program if user inputs the number displayed
      if (GUESS == InputNum)
    {
      std::
        cout << "Hey! you weren't supposed to enter " << GUESS << "!\n";
      break;
    }
      if (GUESS == PATIENCE)
    {
      std::cout << "Wow, you're more patient then I am, you win.\n";
      break;
    }

    }
  while (GUESS != InputNum);

  return 0;
}

初学者编码挑战的麻烦

Trouble with a beginner coding challenge

c++

cout

std

cin