MySQL

Question

我有一个包含以下列的 table：

我想计算有多少客户 (customerID) 有超过一行 (actionVal) 等于 1

我想出了这个 SQL 声明，但运气不佳...

SELECT customerID, SUM(actionVal), COUNT(DISTINCT customerID) as total_C
FROM table1 
GROUP BY customerID 
HAVING SUM(actionVal) > 1

我正在寻找的结果是 ['total_C']

Answer 1

关闭，您只需计算查询中的客户数：

SELECT COUNT(*) as total_C
FROM (
  SELECT customerID, SUM(actionVal)
  FROM table1 
  GROUP BY customerID 
  HAVING SUM(actionVal) > 1
) as q;

Answer 2

您必须计算查询返回的行数。像这样。

SELECT COUNT(1) FROM (
SELECT customerID, SUM(actionVal) as act_sum
FROM table1 
GROUP BY customerID 
HAVING act_sum > 1
) AS tab

希望对您有所帮助。

MySQL - DISTINCT 和 HAVING SUM