ActiveRecord 中的子查询
SubQuery in ActiveRecord
我在 yii2 中有以下模型:
use frontend\modules\bewerber\models\Bewerber;
use common\modules\basis\models\base\Person;
use common\modules\lookup\models\LAnrede;
如何使用 ActiveRecord 的方法创建以下查询?
SELECT anrede FROM L_anrede JOIN Person ON L_anrede.id=Person.id_anrede WHERE Person.id IN
(SELECT id_person FROM Bewerber WHERE Bewerber.id_person=1);
P.S.: 最后一个 WHERE 子句不应该是固定的,而是像这样可变的:
var_dump(LAnrede::findOne([$model->id_person])->anrede)
将输出以下结果:先生或小姐
................................................ .....................
Fabrizio Caldarelli 的提示
................................................ .....................
你的解决方案对我没有帮助:=(
这是你的代码:
$idPerson = 1;
$show=LAnrede::find()->joinWith(['Person' => function($q) use($idPerson) {
$q->andWhere([
'Person.id' => (new \yii\db\Query())->from('Bewerber')->where(['Bewerber.id_person' => $idPerson])
])->anrede;
}]);
这是var_dump($show);
E:\xampp\htdocs\yii2_perswitch\frontend\modules\bewerber\views\bewerber\index.php:48:
object(common\modules\lookup\models\LAnredeQuery)[207]
public 'sql' => null
public 'on' => null
public 'joinWith' =>
array (size=1)
0 =>
array (size=3)
0 =>
array (size=1)
...
1 => boolean true
2 => string 'LEFT JOIN' (length=9)
public 'select' => null
public 'selectOption' => null
public 'distinct' => null
public 'from' => null
public 'groupBy' => null
public 'join' => null
public 'having' => null
public 'union' => null
public 'params' =>
array (size=0)
empty
private '_events' (yii\base\Component) =>
array (size=0)
empty
private '_behaviors' (yii\base\Component) =>
array (size=0)
empty
public 'where' => null
public 'limit' => null
public 'offset' => null
public 'orderBy' => null
public 'indexBy' => null
public 'emulateExecution' => boolean false
public 'modelClass' => string 'common\modules\lookup\models\LAnrede' (length=36)
public 'with' => null
public 'asArray' => null
public 'multiple' => null
public 'primaryModel' => null
public 'link' => null
public 'via' => null
public 'inverseOf' => null
我是这样用Gridview的
$gridColumn = [
[
'attribute' => '',
'label' => Yii::t('app', 'Anrede'),
'format' => 'html',
'value' => function($model) {
return "<p><font color='green'>" . LAnrede::findOne([$model->id_person])->anrede . "</p>";
}
],
];
你能告诉我如何在这种情况下使用你的解决方案吗?
这应该有效:
$idPerson = 1;
LAnrede::find()->joinWith(['Person' => function($q) use($idPerson) {
$q->andWhere([
'Person.id' => (new \yii\db\Query())->from('Bewerber')->where(['Bewerber.id_person' => $idPerson])
]);
}])
->all();
'Person'是LAnrede模型中的一个关系(一个还是多个关系?)
public function getPerson()
{
return $this->hasMany(Person::className(), ['id_anrede' => 'id']);
}
我在 yii2 中有以下模型:
use frontend\modules\bewerber\models\Bewerber;
use common\modules\basis\models\base\Person;
use common\modules\lookup\models\LAnrede;
如何使用 ActiveRecord 的方法创建以下查询?
SELECT anrede FROM L_anrede JOIN Person ON L_anrede.id=Person.id_anrede WHERE Person.id IN
(SELECT id_person FROM Bewerber WHERE Bewerber.id_person=1);
P.S.: 最后一个 WHERE 子句不应该是固定的,而是像这样可变的:
var_dump(LAnrede::findOne([$model->id_person])->anrede)
将输出以下结果:先生或小姐
................................................ .....................
Fabrizio Caldarelli 的提示
................................................ .....................
你的解决方案对我没有帮助:=(
这是你的代码:
$idPerson = 1;
$show=LAnrede::find()->joinWith(['Person' => function($q) use($idPerson) {
$q->andWhere([
'Person.id' => (new \yii\db\Query())->from('Bewerber')->where(['Bewerber.id_person' => $idPerson])
])->anrede;
}]);
这是var_dump($show);
E:\xampp\htdocs\yii2_perswitch\frontend\modules\bewerber\views\bewerber\index.php:48:
object(common\modules\lookup\models\LAnredeQuery)[207]
public 'sql' => null
public 'on' => null
public 'joinWith' =>
array (size=1)
0 =>
array (size=3)
0 =>
array (size=1)
...
1 => boolean true
2 => string 'LEFT JOIN' (length=9)
public 'select' => null
public 'selectOption' => null
public 'distinct' => null
public 'from' => null
public 'groupBy' => null
public 'join' => null
public 'having' => null
public 'union' => null
public 'params' =>
array (size=0)
empty
private '_events' (yii\base\Component) =>
array (size=0)
empty
private '_behaviors' (yii\base\Component) =>
array (size=0)
empty
public 'where' => null
public 'limit' => null
public 'offset' => null
public 'orderBy' => null
public 'indexBy' => null
public 'emulateExecution' => boolean false
public 'modelClass' => string 'common\modules\lookup\models\LAnrede' (length=36)
public 'with' => null
public 'asArray' => null
public 'multiple' => null
public 'primaryModel' => null
public 'link' => null
public 'via' => null
public 'inverseOf' => null
我是这样用Gridview的
$gridColumn = [
[
'attribute' => '',
'label' => Yii::t('app', 'Anrede'),
'format' => 'html',
'value' => function($model) {
return "<p><font color='green'>" . LAnrede::findOne([$model->id_person])->anrede . "</p>";
}
],
];
你能告诉我如何在这种情况下使用你的解决方案吗?
这应该有效:
$idPerson = 1;
LAnrede::find()->joinWith(['Person' => function($q) use($idPerson) {
$q->andWhere([
'Person.id' => (new \yii\db\Query())->from('Bewerber')->where(['Bewerber.id_person' => $idPerson])
]);
}])
->all();
'Person'是LAnrede模型中的一个关系(一个还是多个关系?)
public function getPerson()
{
return $this->hasMany(Person::className(), ['id_anrede' => 'id']);
}