为什么不使用 static_assert 打印换行符/其他控制序列？

Question

int main(int argc, char **argv) {
    static_assert(false, R"error(This is an error message.  You need to

1. Pick up the phone.
2. Call GhostBusters.
3. Run and hide.

)error");
}

给予

error: static_assert failed "This is an error message. You need to\n\n1. Pick up the phone.\n2. Call GhostBusters.\n3. Run and hide.\n\n"
    static_assert(false, err);
    ^             ~~~~~
1 error generated.

有人知道这些是 "unescaped" 的原因吗？它是否依赖于编译器/平台？标准的一部分？

Answer 1

GCC 为您提供所需的换行符：https://godbolt.org/g/jS7Sgm

确切的表示取决于编译器。是否打印转义码可能最好描述为 "quality of implementation" 问题。

Answer 2

标准无外乎：

the resulting diagnostic message (4.1) shall include the text of the string-literal, if one is supplied, except that characters not in the basic source character set (5.3) are not required to appear in the diagnostic message.

换行符是基本源字符集的一部分，因此 "appear" 需要换行符。 它们如何出现与标准控件无关。

为什么不使用 static_assert 打印换行符/其他控制序列？

why aren't newlines / other control sequences printed with static_assert?

c++11

string-literals

static-assert