Laravel 5.5 API collections 的资源(独立数据)
Laravel 5.5 API resources for collections (standalone data)
我想知道是否可以为项目资源和 collection 资源定义不同的数据。
对于 collection 我只想发送 ['id', 'title', 'slug']
但项目资源将包含额外的详细信息 ['id', 'title', 'slug', 'user', etc.]
我想实现这样的目标:
class PageResource extends Resource
{
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
'user' => [
'id' => $this->user->id,
'name' => $this->user->name,
'email' => $this->user->email,
],
];
}
}
class PageResourceCollection extends ResourceCollection
{
/**
* Transform the resource collection into an array.
*
* @param \Illuminate\Http\Request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
];
}
}
PageResourceCollection 将无法按预期工作,因为它使用 PageResource 所以它需要
return [
'data' => $this->collection,
];
我可以将资源复制到 PageFullResource
/ PageListResource
和 PageFullResourceCollection
/ PageListResourceCollection
中,但我正在尝试找到一种更好的方法来实现相同的结果。
资源 class 上有一个收集方法。您可以 return 将其作为 ResourceCollection 的参数输入,然后在该集合上指定您的转换。
控制器:
class PageController extends Controller
{
public function index()
{
return new PageResourceCollection(PageResource::collection(Page::all()));
}
public function show(Page $page)
{
return new PageResource($page);
}
}
资源:
class PageResource extends Resource
{
public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
'user' => [
'id' => $this->user->id,
'name' => $this->user->name,
'email' => $this->user->email,
],
];
}
}
class PageResourceCollection extends ResourceCollection
{
public function toArray($request)
{
return [
'data' => $this->collection->transform(function($page){
return [
'id' => $page->id,
'title' => $page->title,
'slug' => $page->slug,
];
}),
];
}
}
如果您对使用链接和元数据不感兴趣,则接受的答案有效。如果需要,只需 return:
return new PageResourceCollection(Page::paginate(10));
在你的控制器中。在传递到资源集合之前,您还应该期待加载其他依赖关系。
如果希望Resource和Collection中的响应字段具有相同的值,可以在Collection中复用Resource
PersonResource.php
<?php
namespace App\Http\Resources;
use Illuminate\Http\Resources\Json\Resource;
class PersonResource extends Resource
{
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request $request
* @return array
*/
public function toArray($request)
{
// return parent::toArray($request);
return [
'id' => $this->id,
'person_type' => $this->person_type,
'first_name' => $this->first_name,
'last_name' => $this->last_name,
'created_at' => (string) $this->created_at,
'updated_at' => (string) $this->updated_at,
];
}
}
PersonCollection.php
<?php
namespace App\Http\Resources;
use Illuminate\Http\Resources\Json\ResourceCollection;
class PersonCollection extends ResourceCollection
{
/**
* Transform the resource collection into an array.
*
* @param \Illuminate\Http\Request $request
* @return \Illuminate\Http\Resources\Json\AnonymousResourceCollection
*/
public function toArray($request)
{
// return parent::toArray($request);
return PersonResource::collection($this->collection);
}
}
我想知道是否可以为项目资源和 collection 资源定义不同的数据。
对于 collection 我只想发送 ['id', 'title', 'slug']
但项目资源将包含额外的详细信息 ['id', 'title', 'slug', 'user', etc.]
我想实现这样的目标:
class PageResource extends Resource
{
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
'user' => [
'id' => $this->user->id,
'name' => $this->user->name,
'email' => $this->user->email,
],
];
}
}
class PageResourceCollection extends ResourceCollection
{
/**
* Transform the resource collection into an array.
*
* @param \Illuminate\Http\Request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
];
}
}
PageResourceCollection 将无法按预期工作,因为它使用 PageResource 所以它需要
return [
'data' => $this->collection,
];
我可以将资源复制到 PageFullResource
/ PageListResource
和 PageFullResourceCollection
/ PageListResourceCollection
中,但我正在尝试找到一种更好的方法来实现相同的结果。
资源 class 上有一个收集方法。您可以 return 将其作为 ResourceCollection 的参数输入,然后在该集合上指定您的转换。
控制器:
class PageController extends Controller
{
public function index()
{
return new PageResourceCollection(PageResource::collection(Page::all()));
}
public function show(Page $page)
{
return new PageResource($page);
}
}
资源:
class PageResource extends Resource
{
public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
'user' => [
'id' => $this->user->id,
'name' => $this->user->name,
'email' => $this->user->email,
],
];
}
}
class PageResourceCollection extends ResourceCollection
{
public function toArray($request)
{
return [
'data' => $this->collection->transform(function($page){
return [
'id' => $page->id,
'title' => $page->title,
'slug' => $page->slug,
];
}),
];
}
}
如果您对使用链接和元数据不感兴趣,则接受的答案有效。如果需要,只需 return:
return new PageResourceCollection(Page::paginate(10));
在你的控制器中。在传递到资源集合之前,您还应该期待加载其他依赖关系。
如果希望Resource和Collection中的响应字段具有相同的值,可以在Collection中复用Resource
PersonResource.php
<?php
namespace App\Http\Resources;
use Illuminate\Http\Resources\Json\Resource;
class PersonResource extends Resource
{
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request $request
* @return array
*/
public function toArray($request)
{
// return parent::toArray($request);
return [
'id' => $this->id,
'person_type' => $this->person_type,
'first_name' => $this->first_name,
'last_name' => $this->last_name,
'created_at' => (string) $this->created_at,
'updated_at' => (string) $this->updated_at,
];
}
}
PersonCollection.php
<?php
namespace App\Http\Resources;
use Illuminate\Http\Resources\Json\ResourceCollection;
class PersonCollection extends ResourceCollection
{
/**
* Transform the resource collection into an array.
*
* @param \Illuminate\Http\Request $request
* @return \Illuminate\Http\Resources\Json\AnonymousResourceCollection
*/
public function toArray($request)
{
// return parent::toArray($request);
return PersonResource::collection($this->collection);
}
}