从文件路径初始化对象变量

Question

servername
|-- reports
|    |-- ABC
|    |    |-- COB02May2017
|    |    |    |-- pnlreport.pdf
|    |    |    |-- balancereport.pdf
|    |    |-- COB03May2017
|    |-- CustomerB
|    |    |-- COB02May2017
|    |    |-- COB03May2017
|    |    |    |-- balancereport.pdf 
|    |-- 01CFG
|    |    |-- COB03Sep2017

我有上面的目录树来保存我的客户报告。

我有以下 ReportDeliverable 型号：

public class ReportDeliverable {

    private String reportId;
    private String reportName;
    private String customer;
    private String format;
    private Date cobDate;
}

ReportSchedule:

public class ReportSchedule {

    private final String schedule;
    private final String reportId;
    private final String filePattern;
    private final String format;
    private final String filePath;

}

我有以下 class 负责提供报告可交付对象列表：

@Service
public class FileServiceImpl implements FileService {


    @Value("${reports.source-path}")
    private String sourcePath;


    @Override
    public List<ReportDeliverable> getReportDeliverables(ReportSchedule reportSchedule) {
        List<ReportDeliverable> reportDeliverables = new ArrayList<>();
        List<Path> filesToProcess = getFilesToProcess(reportSchedule);

        filesToProcess.forEach(path -> {
            //for each path returned, extract and initialise ReportDeliverable object
            ReportDeliverable reportDeliverable = new ReportDeliverable();
            //reportDeliverable.setReportName(); > pnlreport.xls
            //reportDeliverable.setFormat(); >  > PDF
            //reportDeliverable.setCobDate(); > 26-SEP-2017
            //reportDeliverable.setClient(); > CustomerA
            //reportDeliverable.setFilePath(); > \servername\reports\CustomerA\COB26Sep2017\pnlreport.pdf

            reportDeliverables.add(reportDeliverable); 
        });

        return reportDeliverables;
    }

    public List<Path> getFilesToProcess(ReportSchedule reportSchedule) {

        String pattern = reportSchedule.getFilePattern(); //e.g. pnlreport
        String format = reportSchedule.getFormat(); // PDF

        //return full paths from here based on report criteria for COB that is T-1 (day before today). ignore the rest
        // e.g. if today is 27/09/2017
        //return -> \servername\reports\CustomerA\COB26Sep2017\pnlreport.pdf, \servername\reports\CustomerB\COB26Sep2017\pnlreport.PDF

        return path;
    }
}

每天都会创建一个目录，名称为 COB-{prior-day-date}，如上目录结构。 Java 8,

我需要一些帮助来返回与 ReportSchedules 中的标准有关的所有文件 paths。我试图在 getFilesToProcess(ReportSchedule reportSchedule)
从路径中，我需要初始化 ReportDeliverable 字段，再次在评论中解释 getReportDeliverables(ReportSchedule reportSchedule)

Answer 1

我对您的问题的理解是如何通过目录结构追溯查找符合特定模式的文件，这些文件的命名方式包括遵循特定格式规则的格式化日期。这是我想出的。可以进行优化，但这应该是一个起点。

如果我理解错了你的问题，你可以改一下，这样我就可以更正我的答案。

import java.io.File;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.List;
import java.util.Locale;

public class RetrievePathsOfYesterday {

    public final static void main(String[] args) {
        String pattern = "pnlreport";
        String format = "PDF";
        String baseDir = "F:/Test";
        switch(args.length) {
        case 3:
            format = args[2];
        case 2:
            pattern = args[1];
        case 1:
            baseDir = args[0];
        }
        File root = new File(baseDir);
        File[] customerDirs = root.listFiles(file -> file.getName().toLowerCase(Locale.ENGLISH).startsWith("customer"));
        ArrayList<Path> result = new ArrayList<>();
        for (int i = 0; i < customerDirs.length; i++) {
            result.addAll(getFilesToProcess(customerDirs[i], pattern, format));
        }
        System.out.println(result);
    }

    public static List<Path> getFilesToProcess(File baseDir, String pattern, String format) {
        pattern = pattern.toLowerCase(Locale.ENGLISH);
        format = "." + format.toLowerCase(Locale.ENGLISH);
        Calendar now = Calendar.getInstance();
        now.add(Calendar.DAY_OF_YEAR, -1);
        SimpleDateFormat sdf = new SimpleDateFormat("ddMMMyyyy", Locale.ENGLISH);
        File startDir = new File(baseDir, "COB" + sdf.format(now.getTime()));
        ArrayList<Path> result = new ArrayList<>();
        getFilesToProcess(result, startDir, pattern, format);
        return result;
    }

    private static void getFilesToProcess(List<Path> resList, File baseDir, String pattern, String format) {
        System.out.println("processing " + baseDir.getAbsolutePath());
        if (!baseDir.exists()) {
            return;
        }
        File[] files = baseDir.listFiles(pathName -> {
            System.out.println("filter " + pathName.getName());
            if (pathName.isDirectory()) {
                return true;
            }
            if (!pathName.isFile()) {
                return false;
            }
            String name = pathName.getName().toLowerCase(Locale.ENGLISH);
            if (!name.startsWith(pattern)) {
                return false;
            }
            if (!name.endsWith(format)) {
                return false;
            }
            return true;
        });

        for (int i = 0; i < files.length; i++) {
            File current = files[i];
            System.out.println("Checking " + current.getAbsolutePath());
            if (current.isDirectory()) {
                getFilesToProcess(resList, current, pattern, format);
                continue;
            }
            resList.add(Paths.get(current.toURI()));
        }
    }
}

我用以下目录结构测试了这段代码：

kimmerin@harry /cygdrive/f
$ ls -R Test
Test:
CustomerA  CustomerB

Test/CustomerA:
COB26Sep2017

Test/CustomerA/COB26Sep2017:
pnlreport.pdf

Test/CustomerB:
COB26Sep2017

Test/CustomerB/COB26Sep2017:
otherreport.PDF

如果将 Test 替换为 servername/report，这应该与您在问题中描述的结构完全一样。这是使用默认值启动 class 时的输出：

filter pnlreport.pdf

Checking F:\Test\CustomerA\COB26Sep2017\pnlreport.pdf

processing F:\Test\CustomerB\COB26Sep2017

filter otherreport.PDF

[F:\Test\CustomerA\COB26Sep2017\pnlreport.pdf]

从文件路径初始化对象变量

initialise object variable from file paths

java

nio

java-io

file-processing