Python 根据字典中的条件查找对象值

Question

我从 python 请求中得到低于 json 的数据：

{
    "results": [
        {
            "name": "virtual-machine-1",
            "guest": "Microsoft Windows Server 2016 (64-bit)",
            "status": "green",
            "id": "567890-004",
        },
        {
            "name": "virtual-machine-2",
            "guest": "CoreOS Linux (64-bit)",
            "status": "green",
            "id": "567890-005",
        }
    ]
}

如何根据 "name" 值获取所有词典的 "id" 值。

我已经看到了基于键查找值的解决方案，而不是在同一字典中基于条件查找值并针对多个字典对其进行迭代。感谢您的帮助。

Answer 1

那是重新输入 id:

>>> {result['id']: result['name'] for result in data['results']}
{'567890-004': 'virtual-machine-1', '567890-005': 'virtual-machine-2'}

这种技术称为词典理解。

Answer 2

d = {result['name']: result['id'] for result in request.dict['results'] if 'name' in result}
# request.dict is the name of the object that contains the list "results"

Answer 3

将您的 json 转换为词典列表。那就用简写形式来表达吧。

results = [
{ "name": "virtual-machine-1",
            "guest": "Microsoft Windows Server 2016 (64-bit)",
            "status": "green",
            "id": "567890-004"},
{"name": "virtual-machine-2",
            "guest": "CoreOS Linux (64-bit)",
            "status": "green",
            "id": "567890-005"}
]

id = [x['id'] for x in results if x['name'] == "virtual-machine-1"]
print id    # prints 567890-004

id = [x['id'] for x in results if x['name'] == "virtual-machine-2"]
print id    # prints 567890-005

Python 根据字典中的条件查找对象值

Python find obj value based on condition within dictionary

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