如何在 csv 中的每个单元格中递增数据以及一些问题[python]

Question

我写了一段代码，可以从网页上抓取一些细节。我的问题是，每当我运行我的代码时，它都会打印如下输出：

|['Kapil Sarawagi' 'ksdesigngroup@gmail.com' '1412702594']| |['MA ARCHICTECTS PRIVATE LIMITED' 'studio@maarchitects.in' '1414299999']| |['Prabhu Dayal Kanojiya' 'prabhudayalkanojiya@yahoo.in' '9829055412']|

不过我希望它是这样的。

|['Kapil Sarawagi' 'ksdesigngroup@gmail.com' '1412702594']|

|['MA ARCHICTECTS PRIVATE LIMITED' 'studio@maarchitects.in' '1414299999']|

|['Prabhu Dayal Kanojiya' 'prabhudayalkanojiya@yahoo.in' '9829055412']|

就像在每个单元格中...我该怎么做？

第二个问题，如何让我的代码看起来专业？我的编码风格不好吗？我怎样才能让它更短？下面是我的代码：

import requests
from bs4 import BeautifulSoup
from urllib.request import urlopen
import csv

url = "http://www.rera-rajasthan.in/Home/ViewProject?id=JgMAAA"

html = urlopen(url)
soup = BeautifulSoup(html, "html.parser")
finaldata = []
data = soup.find_all("div", {"class":"panel-body"})

#filename = "Rajasthan.csv"
#f = open(filename, "r")


for i in data:# to get engineer
    date = i.find_all("table", {"class":"table table-bordered"})
    getname = date[21].find_all("td")
    name = getname[1].text
    email = getname[0].text
    phone = getname[3].text
    sublist = []
    fname = [name, email, phone]
    sublist.append(fname)
    for i in data:# to extract architect
        date = i.find_all("table", {"class":"table table-bordered"})
        getname = date[20].find_all("td")
        name = getname[1].text
        email = getname[0].text
        phone = getname[3].text
        #sublist = []
        fname = [name, email, phone]
        sublist.append(fname)
        for i in data:# to extract contractor
            date = i.find_all("table", {"class":"table table-bordered"})
            getname = date[19].find_all("td")
            name = getname[1].text
            email = getname[0].text
            phone = getname[3].text
            #sublist = []
            fname = [name, email, phone]
            sublist.append(fname)
finaldata.append(sublist)
with open("output.csv", "w")as csvfile:
    writer = csv.writer(csvfile, delimiter=',',quotechar='|', lineterminator='\n')
    for i in range(0, len(finaldata)):
        writer.writerow(finaldata[i])

Answer 1

实现相同目标的更短代码：

import requests
from lxml import html

response = requests.get('http://www.rera-rajasthan.in/Home/ViewProject?id=JgMAAA')
tree = html.fromstring(response.content)

# Getting al <h3> tags with 'TableHeading' class
for heading in tree.xpath('//h3[@class="TableHeading"]'):
    # Extracting <h3> heading name/text
    heading_name = heading.xpath('text()')[0]

    # Checking if <h3> heading name has one of these names
    # We only want to get data from the table next to each one of them
    if heading_name in ['CONTRACTOR', 'ARCHITECT', 'STRUCTURAL ENGINEER']:
        # As each table heading has a table below (following-sibling) them
        # We extract the data from that only table (table[1])
        email, name, address, phone = heading.xpath('.//following-sibling::table[1]//tr/td/text()')
        print [name, email, phone]

结果：

['Prabhu Dayal Kanojiya', 'prabhudayalkanojiya@yahoo.in', '9829055412']
['MA ARCHICTECTS PRIVATE LIMITED', 'studio@maarchitects.in', '1414299999']
['Kapil Sarawagi', 'ksdesigngroup@gmail.com', '1412702594']

如何在 csv 中的每个单元格中递增数据以及一些问题[python]

How to increament data in every cell in csv and few questions[python]

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