当退房时间为中午 12 点时，根据入住到退房计算停留天数

Question

<?php
    $today = date('Y-m-d');
    $sql = "SELECT * FROM roombooking where enddate>='$today'" ;

    $result1 = $db->query($sql);
    if ($result1->num_rows > 0){
    echo"
    <div class=table-responsive border >
      <table class=table>
        <tr>

        <th>Room Type</th>
        <th>Room Number</th>
        <th> Status </th>
        <th> Check-in date </th>
        <th> Check-Out date  </th>
        <th>Stay Time</th>
        <th colspan='2'>Action </th>
        </tr>";
        // output data of each row

        // output data of each row
        while ($row = $result1->fetch_assoc()) 
        { echo "<tr>
               <td>".$row["roomtype"]."</td>
               <td>".$row["roomnumber"]."</td>
               <td>".$row["bkg_status"]."</td>
               <td>".$d1=$row["bkg_clientintime"]."</td>
               <td>".$d2=$row["bkg_clientouttime"]."</td>


               </tr>";
            }
     echo "</table></div>";
    }else { echo "<br>"."<div class='alert alert-info col col-md-6 col-md-offset-2'> SORRY NO CHEK OUT FOUND FOR TODAY 

    </div> ";}
?>
//here from $d1 which is booking check-in-date and $d2 which is check-out-date 
HELP REQUIRED // important checkout date time is 12.00 noon 
HELP REQUIRED 2// FINDING TOTAL Number of days stay 

any suggestion are greatly appreciated 
tried here date_diff / it again gives hours or days but have to find based on
12.00 noon important checkout otherwise new day will be added  how to achieve this part  kindly guide

Answer 1

这里最简单的方法是计算 mysql

上不同的日期

SELECT *,
  DATE_DIFF(DATE(bkg_clientintime), DATE(bkg_clientouttime)) AS no_days
FROM roombooking

当退房时间为中午 12 点时，根据入住到退房计算停留天数

Calculate days stay based on checkin to checkout when check out time is at 12.00 noon

php

datetime

datediff