Py2neo：查找关系和 return 节点

Question

在不使用 graph.cypher.execute（或获取 graph.cypher.execute 到 return 的一组节点而不是丑陋的 return-字符串)

MATCH (tom:Person {name: "Tom Hanks"})-[:ACTED_IN]->(tomHanksMovies) RETURN tom,tomHanksMovies

我想要的是这样的：

(n4358:Person {born:1956,name:"Tom Hanks"}, {'PLAYED_IN', 'year': 1990}, n4354:Movie {released:1998,tagline:"At odds in life... in love on-line.",title:"You've Got Mail"})

其中 a[0] 给出了 tom hanks 节点，a[1] 给出了关系，a[2] 给出了电影。

编辑：添加了"wrong"示例输出

>>> print('List all Tom Hanks movies...')
>>> a = graph.cypher.execute('MATCH (tom:Person {name: "Tom Hanks"})-[:ACTED_IN]->(tomHanksMovies) RETURN tomHanksMovies')
>>> print(a)

List all Tom Hanks movies...
    | tomHanksMovies                                                                                                                                                                 
----+---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
  1 | (n4354:Movie {released:1998,tagline:"At odds in life... in love on-line.",title:"You've Got Mail"})                                                                            
  2 | (n4360:Movie {released:1993,tagline:"What if someone you never met, someone you never saw, someone you never knew was the only someone for you?",title:"Sleepless in Seattle"})
  3 | (n4365:Movie {released:1990,tagline:"A story of love, lava and burning desire.",title:"Joe Versus the Volcano"})                                                               
  4 | (n4372:Movie {released:1996,tagline:"In every life there comes a time when that thing you dream becomes that thing you do",title:"That Thing You Do"})                         
  5 | (n4392:Movie {released:2012,tagline:"Everything is connected",title:"Cloud Atlas"})                                                                                            
  6 | (n4398:Movie {released:2006,tagline:"Break The Codes",title:"The Da Vinci Code"})                                                                                              
  7 | (n4417:Movie {released:1999,tagline:"Walk a mile you'll never forget.",title:"The Green Mile"})                                                                                
  8 | (n4431:Movie {released:1995,tagline:"Houston, we have a problem.",title:"Apollo 13"})                                                                                          
  9 | (n4437:Movie {released:2000,tagline:"At the edge of the world, his journey begins.",title:"Cast Away"})                                                                        
 10 | (n4446:Movie {released:2007,tagline:"A stiff drink. A little mascara. A lot of nerve. Who said they couldn't bring down the Soviet empire.",title:"Charlie Wilson's War"})     
 11 | (n4448:Movie {released:2004,tagline:"This Holiday Season… Believe",title:"The Polar Express"})                                                                                 
 12 | (n4449:Movie {released:1992,tagline:"Once in a lifetime you get a chance to do something different.",title:"A League of Their Own"})   


>>> print(a[0])

 tomHanksMovies                                                                                     
-----------------------------------------------------------------------------------------------------
 (n4354:Movie {released:1998,tagline:"At odds in life... in love on-line.",title:"You've Got Mail"})

>>> print(type(a[0]))

<class 'py2neo.cypher.core.Record'>

Answer 1

如果您已经习惯使用 py2neo，您可以稍微修改您的查询以 return 您想要的所有信息。例如，

a = graph.cypher.execute("MATCH (a:Person {name:"Tom Hanks"})-[acted:ACTED_IN]->(movies:Movie) RETURN a, acted, movies")

它应该做的是在列表中给你结果，就像你说你不想要的那样。但是，从这里您可以为结果编制索引以获得您想要的每个部分。例如，a[0] 将为您提供第一行结果，a[0][0] 将为您提供第一行结果中的人员节点，a[0][0][0] 将为您提供第一行第一个节点的第一个属性，等等。从这里您可以运行一个 for 循环将结果组织成您更感兴趣的形式。

希望对您有所帮助。

Answer 2

我想您已经意识到 execute 实际上 return 不是一个字符串？您在 a 中看到的是文档中指定的 RecordList 的表示形式：

http://py2neo.org/2.0/cypher.html#py2neo.cypher.CypherResource.execute

a[0] 然后给你 RecordList 中的第一个 Record。然后可以通过名称访问 Record 中的值，例如a[0]['tomHanksMovies'].

Record 个对象的详细信息在此处：

http://py2neo.org/2.0/cypher.html#records

Py2neo：查找关系和 return 节点

Py2neo: Find relations and return nodes

python

neo4j

py2neo