如何实现SimpleMiddleware？

Question

我正在努力让 MiddleWare 工作。我把这个放在我的 settings.py:

MIDDLEWARE_CLASSES = [
    'django.middleware.security.SecurityMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.common.CommonMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'django.middleware.clickjacking.XFrameOptionsMiddleware',
    'portal.middleware.SimpleMiddleware'
]

我在 portal/middleware/MiddleWare.py 中实现了这个 class：

class SimpleMiddleware:
    def __init__(self, get_response):
        self.get_response = get_response
        # One-time configuration and initialization.

    def __call__(self, request):
        # Code to be executed for each request before
        # the view (and later middleware) are called.

        response = self.get_response(request)

        # Code to be executed for each request/response after
        # the view is called.

        return response

但是当运行时，我得到 TypeError:

TypeError: __init__() takes exactly 2 arguments (1 given)

Answer 1

由于您正在编写新式中间件，因此您应该在设置中使用 MIDDLEWARE 而不是 MIDDLEWARE_CLASSES。

您还需要确保您在设置中的输入与中间件的位置相匹配。条目 'portal.middleware.SimpleMiddleware' 建议在 portal/middleware.py 中使用 SimpleMiddleware class，这与您的文件名 portal/middleware/MiddleWare.py.

不匹配

如何实现SimpleMiddleware？

How to implement the SimpleMiddleware?

django

django-middleware