cuda - 零拷贝内存,内存映射文件
cuda - Zero-copy memory, memory-mapped file
我正在尝试创建一个包含 uint32_t
s 的映射内存文件,然后将其用作零拷贝固定内存,如下所示用于 CUDA。我在获取设备指针时得到 cudaErrorInvalidValue
,分配了 space 并从文件映射了内存。我知道错误消息(来自 API)的意思是:
This indicates that one or more of the parameters passed to the API call is not within an acceptable range of values.
但我正在努力弄清楚为什么我会遇到这个问题....有什么想法吗?提前致谢。
#include <stdio.h>
#include <stdlib.h>
#include <sys/mman.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
…
int main(void)
{
struct stat buf;
…
uint32_t *data, *dev_data;
cudaDeviceProp cuda_prop;
cudaGetDeviceProperties(&cuda_prop, 0);
if (!cuda_prop.canMapHostMemory)
exit(EXIT_FAILURE);
cudaSetDeviceFlags(cudaDeviceMapHost);
int data_file = open(data_file_name, O_RDONLY);
int stat = fstat(sa_file, &buf);
int data_file_size = buf.st_size;
err = cudaHostAlloc((void**)&data, data_file_size, cudaHostAllocMapped);
if (err == cudaErrorMemoryAllocation) exit(EXIT_FAILURE);
data = (uint32_t*) mmap(0, data_file_size, PROT_READ, MAP_PRIVATE, data_file, 0);
err = cudaHostGetDevicePointer((void**)&dev_data, (void*)data, 0);
if (err == cudaErrorMemoryAllocation)
{
printf("cudaHostGetDevicePointer - Mem Alloc Err\n");
exit(EXIT_FAILURE);
}
else if (err == cudaErrorInvalidValue) //ERROR HERE.
{
printf("cudaHostGetDevicePointer - Invalid Val Err\n");
exit(EXIT_FAILURE);
}
…
}
一个问题是你程序的逻辑顺序不正确。此行为 CUDA API:
提供的 data
赋值
err = cudaHostAlloc((void**)&data, data_file_size, cudaHostAllocMapped);
然后这一行 覆盖 那个值,用一个新值:
data = (uint32_t*) mmap(0, data_file_size, PROT_READ, MAP_PRIVATE, data_file, 0);
此时,CUDA API 不再将 data
的值识别为固定内存 space,因此当您调用它时:
err = cudaHostGetDevicePointer((void**)&dev_data, (void*)data, 0);
你得到一个错误,因为 data
中包含的值无法识别。
编辑:(基于this question)
除了这个问题,似乎如果您将文件处理从只读更改为读写,那么这个过程就可以正常工作(不会引发运行时错误)。这是一个完整的代码(不包含上述逻辑缺陷)来演示这一点(我之前创建了一个大小为 566316 字节的 test.dat
文件):
$ cat t706.cu
#include <stdio.h>
#include <stdlib.h>
#include <sys/mman.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
#include <stdint.h>
int main(void)
{
struct stat buf;
char *dev_data;
cudaDeviceProp cuda_prop;
cudaGetDeviceProperties(&cuda_prop, 0);
if (!cuda_prop.canMapHostMemory)
exit(EXIT_FAILURE);
cudaSetDeviceFlags(cudaDeviceMapHost);
int data_file = open("test.dat", O_RDWR);
int stat = fstat(data_file, &buf);
int data_file_size = buf.st_size;
printf("data_file_size = %d\n", data_file_size);
char *data = (char *) mmap(0, data_file_size, PROT_READ|PROT_WRITE, MAP_PRIVATE, data_file, 0);
if (data == MAP_FAILED) {
printf("mmap failure\n");
exit(EXIT_FAILURE);}
cudaError_t err = cudaHostRegister(data, data_file_size, cudaHostRegisterDefault);
if (err != cudaSuccess) { //ERROR HERE.
printf("cudaHostRegister fail\n");
exit(EXIT_FAILURE);}
err = cudaHostGetDevicePointer((void**)&dev_data, (void*)data, 0);
if (err == cudaErrorMemoryAllocation)
{
printf("cudaHostGetDevicePointer - Mem Alloc Err\n");
exit(EXIT_FAILURE);
}
else if (err == cudaErrorInvalidValue)
{
printf("cudaHostGetDevicePointer - Invalid Val Err\n");
exit(EXIT_FAILURE);
}
}
$ nvcc -arch=sm_30 -o t706 t706.cu
$ ./t706
data_file_size = 566316
$
我正在尝试创建一个包含 uint32_t
s 的映射内存文件,然后将其用作零拷贝固定内存,如下所示用于 CUDA。我在获取设备指针时得到 cudaErrorInvalidValue
,分配了 space 并从文件映射了内存。我知道错误消息(来自 API)的意思是:
This indicates that one or more of the parameters passed to the API call is not within an acceptable range of values.
但我正在努力弄清楚为什么我会遇到这个问题....有什么想法吗?提前致谢。
#include <stdio.h>
#include <stdlib.h>
#include <sys/mman.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
…
int main(void)
{
struct stat buf;
…
uint32_t *data, *dev_data;
cudaDeviceProp cuda_prop;
cudaGetDeviceProperties(&cuda_prop, 0);
if (!cuda_prop.canMapHostMemory)
exit(EXIT_FAILURE);
cudaSetDeviceFlags(cudaDeviceMapHost);
int data_file = open(data_file_name, O_RDONLY);
int stat = fstat(sa_file, &buf);
int data_file_size = buf.st_size;
err = cudaHostAlloc((void**)&data, data_file_size, cudaHostAllocMapped);
if (err == cudaErrorMemoryAllocation) exit(EXIT_FAILURE);
data = (uint32_t*) mmap(0, data_file_size, PROT_READ, MAP_PRIVATE, data_file, 0);
err = cudaHostGetDevicePointer((void**)&dev_data, (void*)data, 0);
if (err == cudaErrorMemoryAllocation)
{
printf("cudaHostGetDevicePointer - Mem Alloc Err\n");
exit(EXIT_FAILURE);
}
else if (err == cudaErrorInvalidValue) //ERROR HERE.
{
printf("cudaHostGetDevicePointer - Invalid Val Err\n");
exit(EXIT_FAILURE);
}
…
}
一个问题是你程序的逻辑顺序不正确。此行为 CUDA API:
提供的data
赋值
err = cudaHostAlloc((void**)&data, data_file_size, cudaHostAllocMapped);
然后这一行 覆盖 那个值,用一个新值:
data = (uint32_t*) mmap(0, data_file_size, PROT_READ, MAP_PRIVATE, data_file, 0);
此时,CUDA API 不再将 data
的值识别为固定内存 space,因此当您调用它时:
err = cudaHostGetDevicePointer((void**)&dev_data, (void*)data, 0);
你得到一个错误,因为 data
中包含的值无法识别。
编辑:(基于this question)
除了这个问题,似乎如果您将文件处理从只读更改为读写,那么这个过程就可以正常工作(不会引发运行时错误)。这是一个完整的代码(不包含上述逻辑缺陷)来演示这一点(我之前创建了一个大小为 566316 字节的 test.dat
文件):
$ cat t706.cu
#include <stdio.h>
#include <stdlib.h>
#include <sys/mman.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
#include <stdint.h>
int main(void)
{
struct stat buf;
char *dev_data;
cudaDeviceProp cuda_prop;
cudaGetDeviceProperties(&cuda_prop, 0);
if (!cuda_prop.canMapHostMemory)
exit(EXIT_FAILURE);
cudaSetDeviceFlags(cudaDeviceMapHost);
int data_file = open("test.dat", O_RDWR);
int stat = fstat(data_file, &buf);
int data_file_size = buf.st_size;
printf("data_file_size = %d\n", data_file_size);
char *data = (char *) mmap(0, data_file_size, PROT_READ|PROT_WRITE, MAP_PRIVATE, data_file, 0);
if (data == MAP_FAILED) {
printf("mmap failure\n");
exit(EXIT_FAILURE);}
cudaError_t err = cudaHostRegister(data, data_file_size, cudaHostRegisterDefault);
if (err != cudaSuccess) { //ERROR HERE.
printf("cudaHostRegister fail\n");
exit(EXIT_FAILURE);}
err = cudaHostGetDevicePointer((void**)&dev_data, (void*)data, 0);
if (err == cudaErrorMemoryAllocation)
{
printf("cudaHostGetDevicePointer - Mem Alloc Err\n");
exit(EXIT_FAILURE);
}
else if (err == cudaErrorInvalidValue)
{
printf("cudaHostGetDevicePointer - Invalid Val Err\n");
exit(EXIT_FAILURE);
}
}
$ nvcc -arch=sm_30 -o t706 t706.cu
$ ./t706
data_file_size = 566316
$