计算多个随机数的平均值 Python

Question

我是 Python 的新手，运行遇到了障碍，试图计算一堆随机数的平均值 numbers.The 该程序的总体概述是一个掷骰子程序，提示用户输入一定数量的面，然后掷骰子直到程序输出蛇眼。它还跟踪滚动的双打数量以及获得蛇眼所需的时间。然后创建在整个程序中为每个骰子滚动的数字的平均值。这就是我迷路的地方。

编辑：我删除了我的原始代码并在 Vasilis 的答案中工作：

import random

while True:
    #prompts user for valid number
    user_s = int (input ("How many sides on your dice? "))
    if user_s < 3:
         print("That is not a valid size value, please enter a positive number")
    if user_s >= 3:
        break

print()
print("Thanks! Here we go...")
print()
double_count = 0 
roll_count = 0

sum1 = 0 # Used to calculate sum of die_1
sum2 = 0 # Used to calculate sum of die_2

while True:
    roll_count += 1
    die_1 = random.randint(1,user_s)   
    die_2 = random.randint (1,user_s)




    print(roll_count,".", " Die number 1 is ", die_1 , " and die number 2 is ", die_2,  ".", sep ="")
    if die_1 == die_2:
        double_count += 1
    if die_1 == 1 and die_2 == 1:
        break

    # Making sum
    sum1 = sum1 + die_1 
    sum2 = sum2 + die_2

print("You finally got snake eyes on try number", roll_count)
print("Along the way you rolled a double", double_count,"times")

print(die_1)
print(die_2)

# Integer divisions

avg_roll1 = sum1 // roll_count
avg_roll2 = sum2 // roll_count


print("The average roll for die 1 was", format(avg_roll1,".2f"))
print("The average roll for die 2 was", avg_roll2)

然而，就像他指出的那样，它并没有采用所有卷中记录的所有数字，而是最后一个数字。任何有助于实现这一目标的帮助将不胜感激。

谢谢！

Answer 1

如果你愿意的话，我对你的代码做了一些修改。我假设您希望将平均值计算为整数，尽管您可以更改它。您使用 die_1 和 die_2 作为简单的整数变量，因此它们仅保存 random.randint(1,user_s):

生成的最后一个值

import random

    '''Skipped input part'''

    print()
    print("Thanks! Here we go...")
    print()
    double_count = 0 
    roll_count = 0

    sum1 = 0 # Used to calculate sum of die_1
    sum2 = 0 # Used to calculate sum of die_2

    while True:
        roll_count += 1
        die_1 = random.randint(1,user_s)   
        die_2 = random.randint (1,user_s)

        print("DIE_1: ", die_1)
        print("DIE_2: ", die_2)


        print(roll_count,".", " Die number 1 is ", die_1 , " and die number 2 is ", die_2,  ".", sep ="")
        if die_1 == die_2:
            double_count += 1
        if die_1 == 1 and die_2 == 1:
            break

        # Making sum
        sum1 = sum1 + die_1 
        sum2 = sum2 + die_2

    print("You finally got snake eyes on try number", roll_count)
    print("Along the way you rolled a double", double_count,"times")

    print(die_1)
    print(die_2)

    # Integer divisions

    avg_roll1 = sum1 // roll_count
    avg_roll2 = sum2 // roll_count


    print("The average roll for die 1 was", avg_roll1)
    print("The average roll for die 2 was", avg_roll2)

Answer 2

我自己搞定了。

将累加器变量 = 设置为掷骰子。在这种情况下，sum1 和 sum2 是变量。

# make all of the functions in the "random" module available to this program
import random

while True:
    #prompts user for valid number
    user_s = int (input ("How many sides on your dice? "))
    if user_s < 3:
         print("That is not a valid size value, please enter a positive number")
    if user_s >= 3:
        break

print()
print("Thanks! Here we go...")
print()
double_count = 0 
roll_count = 0

sum1 = 0 # Used to calculate sum of die_1
sum2 = 0 # Used to calculate sum of die_2

#while statement for die rolls
while True:
    roll_count += 1
    die_1 = random.randint(1,user_s)
    sum1 += die_1

    die_2 = random.randint (1,user_s)
    sum2 += die_2




    print(roll_count,".", " Die number 1 is ", die_1 , " and die number 2 is ", die_2,  ".", sep ="")
    if die_1 == die_2:
        double_count += 1
    if die_1 == 1 and die_2 == 1:
        break



print("You finally got snake eyes on try number", roll_count)
print("Along the way you rolled a double", double_count,"times")


# Integer divisions

avg_roll1 = sum1 / roll_count

avg_roll2 = sum2 / roll_count


print("The average roll for die 1 was", format(avg_roll1,".2f"))
print("The average roll for die 2 was", format(avg_roll2,".2f"))

计算多个随机数的平均值 Python

Calculating an average of multiple random numbers Python

python

python-3.x

python-3.6