我需要使用 python 找到第 9 个正整数，它是 4、13、14、26 和 50 的倍数：

I need to find the 9th positive integer that is a multiple of 4, 13, 14, 26, and 50 using python:

python-3.6

为什么这段代码不起作用？我得到一个连续循环...

solution = 0
multiple = 0
max_bound = 100000
i = 1

while i < max_bound:
    if (i % 4 == 0) and (i % 13 == 0) and (i % 14) and (i % 26 == 0) and (i % 50 == 0):
        multiple += 1
        if multiple == 9:
            solution = i 
            break 
    i += 1 

if multiple == 9:
  print("#1 : 9th Multiple ::", "Correct." if solution == 81900 else ("Wrong: " + str(solution)))

您刚刚错过了 14 验证，您使用 (1 % 14) 而不是 (i % 14 == 0)，其中 returns 0(False) 当数字可以被 14 整除而不是 True 并且使用 and 运算符时它不会进入 if 语句。

solution = 0
multiple = 0
max_bound = 100000
i = 1

while i < max_bound:
    if (i % 4 == 0) and (i % 13 == 0) and (i % 14 == 0) and (i % 26 == 0) and (i % 50 == 0):
        multiple += 1
        if multiple == 9:
            solution = i
            break
    i += 1

if multiple == 9:
    print("#1 : 9th Multiple ::", "Correct." if solution == 81900 else ("Wrong: " + str(solution)))