Java 使用 VLCJ 的 http 流媒体视频 - 您的输入无法打开
Java http Streaming Video with VLCJ - Your input can't be opened
我正在尝试使用 VLCJ 库 Java 编写一个 http 视频流应用程序,但我遇到了问题 "your input can't be opened"。
OS: Windows10 x64
import com.sun.jna.Native;
import com.sun.jna.NativeLibrary;
import uk.co.caprica.vlcj.binding.LibVlc;
import uk.co.caprica.vlcj.player.MediaPlayerFactory;
import uk.co.caprica.vlcj.player.headless.HeadlessMediaPlayer;
import uk.co.caprica.vlcj.runtime.RuntimeUtil;
import uk.co.caprica.vlcj.runtime.x.LibXUtil;
import java.io.File;
/**
* An example of how to stream a media file over HTTP.
* <p>
* The client specifies an MRL of <code>http://127.0.0.1:5555</code>
*/
public class VideoStream extends VlcjTest{
public static void main(String[] args) throws Exception {
System.setProperty("VLC_PLUGIN_PATH", "D:\Program Files\VideoLAN\VLC\plugins");
File vlcInstallPath = new File("D:\Program Files\VideoLAN\VLC");
NativeLibrary.addSearchPath(
RuntimeUtil.getLibVlcLibraryName(), vlcInstallPath.getAbsolutePath());
Native.loadLibrary(RuntimeUtil.getLibVlcLibraryName(), LibVlc.class);
LibXUtil.initialise();
String media = "D://demo.mp4";
String options = formatHttpStream("127.0.0.1", 5555);
System.out.println("Streaming '" + media + "' to '" + options + "'");
MediaPlayerFactory mediaPlayerFactory = new MediaPlayerFactory();
HeadlessMediaPlayer mediaPlayer = mediaPlayerFactory.newHeadlessMediaPlayer();
mediaPlayer.playMedia(media, options);
// Don't exit
Thread.currentThread().join();
}
private static String formatHttpStream(String serverAddress, int serverPort) {
StringBuilder sb = new StringBuilder(60);
sb.append(":sout=#duplicate{dst=std{access=http,mux=ts,");
sb.append("dst=");
sb.append(serverAddress);
sb.append(':');
sb.append(serverPort);
sb.append("}}");
return sb.toString();
}
}
结果:
[000000001a948be0] access_output_http access out: Consider passing --http-host=IP on the command line instead.
[000000001aa2def0] core input error: open of `D://demo.mp4' failed
[000000001aa2def0] core input error: Your input can't be opened
[000000001aa2def0] core input error: VLC is unable to open the MRL 'D://demo.mp4'. Check the log for details.
问题在
String media = "D://demo.mp4";
如评论所建议。 // 在 D:
之后,它将被视为协议名称。
以下变体之一应该适合您:
String media = "D:/demo.mp4";
前提是playMedia
支持本地文件路径。或者
String media = new File("D:/demo.mp4").toURI().toURL();
如果它需要 URL 字符串。
我正在尝试使用 VLCJ 库 Java 编写一个 http 视频流应用程序,但我遇到了问题 "your input can't be opened"。
OS: Windows10 x64
import com.sun.jna.Native;
import com.sun.jna.NativeLibrary;
import uk.co.caprica.vlcj.binding.LibVlc;
import uk.co.caprica.vlcj.player.MediaPlayerFactory;
import uk.co.caprica.vlcj.player.headless.HeadlessMediaPlayer;
import uk.co.caprica.vlcj.runtime.RuntimeUtil;
import uk.co.caprica.vlcj.runtime.x.LibXUtil;
import java.io.File;
/**
* An example of how to stream a media file over HTTP.
* <p>
* The client specifies an MRL of <code>http://127.0.0.1:5555</code>
*/
public class VideoStream extends VlcjTest{
public static void main(String[] args) throws Exception {
System.setProperty("VLC_PLUGIN_PATH", "D:\Program Files\VideoLAN\VLC\plugins");
File vlcInstallPath = new File("D:\Program Files\VideoLAN\VLC");
NativeLibrary.addSearchPath(
RuntimeUtil.getLibVlcLibraryName(), vlcInstallPath.getAbsolutePath());
Native.loadLibrary(RuntimeUtil.getLibVlcLibraryName(), LibVlc.class);
LibXUtil.initialise();
String media = "D://demo.mp4";
String options = formatHttpStream("127.0.0.1", 5555);
System.out.println("Streaming '" + media + "' to '" + options + "'");
MediaPlayerFactory mediaPlayerFactory = new MediaPlayerFactory();
HeadlessMediaPlayer mediaPlayer = mediaPlayerFactory.newHeadlessMediaPlayer();
mediaPlayer.playMedia(media, options);
// Don't exit
Thread.currentThread().join();
}
private static String formatHttpStream(String serverAddress, int serverPort) {
StringBuilder sb = new StringBuilder(60);
sb.append(":sout=#duplicate{dst=std{access=http,mux=ts,");
sb.append("dst=");
sb.append(serverAddress);
sb.append(':');
sb.append(serverPort);
sb.append("}}");
return sb.toString();
}
}
结果:
[000000001a948be0] access_output_http access out: Consider passing --http-host=IP on the command line instead.
[000000001aa2def0] core input error: open of `D://demo.mp4' failed
[000000001aa2def0] core input error: Your input can't be opened
[000000001aa2def0] core input error: VLC is unable to open the MRL 'D://demo.mp4'. Check the log for details.
问题在
String media = "D://demo.mp4";
如评论所建议。 // 在 D:
之后,它将被视为协议名称。
以下变体之一应该适合您:
String media = "D:/demo.mp4";
前提是playMedia
支持本地文件路径。或者
String media = new File("D:/demo.mp4").toURI().toURL();
如果它需要 URL 字符串。