C++98 和 C++11 之间的哪些变化显示出行为差异?

What changes between C++98 and C++11 show difference in behavior?

我正在阅读以下内容post:

还有 isocpp 页面:

所以我开始好奇,根据标准:C++11 中引入的哪些更改可能会破坏用 C++98 编写的程序?

突出的大问题 -- 从析构函数中抛出异常。

在 C++98 中,如果您小心的话,您可以拥有执行此操作的程序并且可以正常工作。

在 C++11 中,您通常必须显式声明 dtor noexcept(false)

很好 blog post here,在 Andrzej 的 C++ 博客上。

In short, the following program used to run successfully in C++03 (under some definition of “success”):

struct S
{
  ~S() { throw runtime_error(""); } // bad, but acceptable
}; 

int main()
{
  try { S s; }
  catch (...) {
    cerr << "exception occurred";
  } 
  cout << "success";
}

In C++11, the same program will trigger the call to std::terminate.

这是另一个与 C++11 中的析构函数 are noexcept(true) 相关的案例:

// A simple program that demonstrates how C++11 and pthread_cancel don't play
// nicely together.
//
// If you build without C++11 support (g++ threadkill.cpp -lpthread), the
// application will work as expected. After 5 seconds, main() will cancel the
// thread it created and the program will successfully exit.
//
// If you build with C++11 support(g++ -std=c++11 threadkill.cpp -lpthread),
// the program will crash because the abi::__forced_unwind exception will
// escape the destructor, which is implicitly marked as noexcept(true) in
// C++11. If you mark the destructor as noexcept(false), the program does 
// not crash.
#include <iostream>
#include <unistd.h>
#include <string.h>

class sleepyDestructorObject
{
public:
    ~sleepyDestructorObject() //noexcept(false)
    {
        std::cout << "sleepy destructor invoked" << std::endl;
        while(true)
        {
            std::cout << "." << std::flush;
            sleep(1);
        }
    }
};

void* threadFunc( void* lpParam )
{
    sleepyDestructorObject sleepy;
    return NULL;
}

int main(int argc, char** argv)
{
    pthread_t tThreadID;
    pthread_create(&tThreadID, NULL, threadFunc, NULL);
    sleep(5);
    pthread_cancel(tThreadID);
    pthread_join(tThreadID, NULL);
    return 0;
}

原始参考: