可以简化 SQL 吗？

Question

此查询的目的是计算 "same" 类型商品的四种不同变体的每个唯一 ID (LUID_NO)。它按预期工作。
现在我的问题是，这个查询是否可以简化或以其他方式编写？
当我看到它时，我无法摆脱这样一种感觉，即可能可以用另一种更简单的方式来编写它。

SELECT 
    (SELECT COUNT(DISTINCT ICL.LUID_NO) 
             FROM       L2000.ITEM_CARRIER IC
             INNER JOIN L2000.ITEM_UNITS_DEFINITION IUD ON IUD.PV_ID=IC.PV_ID AND IUD.STORER_ID=IC.STORER_ID AND IUD.ITEM_ID=IC.ITEM_ID
             INNER JOIN L2000.ITEM_CARRIER_LUID ICL ON ICL.ITEM_CARRIER_NO=IC.ITEM_CARRIER_NO
             INNER JOIN L2000.ITEM_PROPERTY IP ON IC.PROPERTY_INDEX=IP.PROPERTY_INDEX
             INNER JOIN L2000.ITEM I ON I.ITEM_ID = IC.ITEM_ID AND I.STORER_ID = IC.STORER_ID
                   WHERE     IC.PV_ID = 'B2' 
                   AND       IP.BLOCK_CODE IS NULL 
                   AND       IUD.UOM_QTY = ICL.PHYSIC_QTY 
                   AND       IUD.UNIT_DEF_ID = 'LU' 
                   AND       IC.STORER_ID = 'PG' 
                   AND       ICL.PHYSIC_QTY > 0  
                   AND       I.ITEM_DESC LIKE '#%' 
                   AND       I.ITEM_GROUP_ID IN ('BABYCARE','FEMCARE')
    )AS B2_PALLETS,
   (SELECT COUNT(DISTINCT ICL.LUID_NO) 
             FROM       L2000.ITEM_CARRIER IC
             INNER JOIN L2000.ITEM_UNITS_DEFINITION IUD ON IUD.PV_ID=IC.PV_ID AND IUD.STORER_ID=IC.STORER_ID AND IUD.ITEM_ID=IC.ITEM_ID
             INNER JOIN L2000.ITEM_CARRIER_LUID ICL ON ICL.ITEM_CARRIER_NO=IC.ITEM_CARRIER_NO
             INNER JOIN L2000.ITEM_PROPERTY IP ON IC.PROPERTY_INDEX=IP.PROPERTY_INDEX
             INNER JOIN L2000.ITEM I ON I.ITEM_ID = IC.ITEM_ID AND I.STORER_ID = IC.STORER_ID
                   WHERE    IC.PV_ID = 'B3' 
                   AND      IP.BLOCK_CODE IS NULL 
                   AND      IUD.UOM_QTY = ICL.PHYSIC_QTY 
                   AND      IUD.UNIT_DEF_ID = 'LU' 
                   AND      IC.STORER_ID = 'PG' 
                   AND      ICL.PHYSIC_QTY > 0 
                   AND      I.ITEM_DESC LIKE '#%' 
                   AND      I.ITEM_GROUP_ID IN ('BABYCARE','FEMCARE')
    )AS B3_PALLETS,
   (SELECT COUNT(DISTINCT ICL.LUID_NO) 
             FROM       L2000.ITEM_CARRIER IC
             INNER JOIN L2000.ITEM_UNITS_DEFINITION IUD ON IUD.PV_ID=IC.PV_ID AND IUD.STORER_ID=IC.STORER_ID AND IUD.ITEM_ID=IC.ITEM_ID
             INNER JOIN L2000.ITEM_CARRIER_LUID ICL ON ICL.ITEM_CARRIER_NO=IC.ITEM_CARRIER_NO
             INNER JOIN L2000.ITEM_PROPERTY IP ON IC.PROPERTY_INDEX=IP.PROPERTY_INDEX
             INNER JOIN L2000.ITEM I ON I.ITEM_ID = IC.ITEM_ID AND I.STORER_ID = IC.STORER_ID
                   WHERE    IC.PV_ID = 'B2' 
                   AND      IP.BLOCK_CODE IS NOT NULL 
                   AND      IUD.UNIT_DEF_ID = 'LU' 
                   AND      IC.STORER_ID = 'PG' 
                   AND      ICL.PHYSIC_QTY > 0 
                   AND      I.ITEM_DESC LIKE '#%' 
                   AND      I.ITEM_GROUP_ID IN ('BABYCARE','FEMCARE')
    )AS BLOCKED_B2_PALLETS,
   (SELECT COUNT(DISTINCT ICL.LUID_NO) 
             FROM       L2000.ITEM_CARRIER IC
             INNER JOIN L2000.ITEM_UNITS_DEFINITION IUD ON IUD.PV_ID=IC.PV_ID AND IUD.STORER_ID=IC.STORER_ID AND IUD.ITEM_ID=IC.ITEM_ID
             INNER JOIN L2000.ITEM_CARRIER_LUID ICL ON ICL.ITEM_CARRIER_NO=IC.ITEM_CARRIER_NO
             INNER JOIN L2000.ITEM_PROPERTY IP ON IC.PROPERTY_INDEX=IP.PROPERTY_INDEX
             INNER JOIN L2000.ITEM I ON I.ITEM_ID = IC.ITEM_ID AND I.STORER_ID = IC.STORER_ID
                   WHERE    IC.PV_ID = 'B3' 
                   AND      IP.BLOCK_CODE IS NOT NULL 
                   AND      IUD.UNIT_DEF_ID = 'LU' 
                   AND      IC.STORER_ID = 'PG' 
                   AND      ICL.PHYSIC_QTY > 0
                   AND      I.ITEM_DESC LIKE '#%' 
                   AND      I.ITEM_GROUP_ID IN ('BABYCARE','FEMCARE')
    )AS BLOCKED_B3_PALLETS

FROM   L2000.ITEM_CARRIER
WHERE  ROWNUM = 1

Answer 1

使用条件聚合

 SELECT COUNT(DISTINCT CASE WHEN IC.PV_ID = 'B2' 
               AND      IP.BLOCK_CODE IS NULL THEN ICL.LUID_NO END) AS B2_PALLETS,
        COUNT(DISTINCT CASE WHEN IC.PV_ID = 'B3' 
               AND      IP.BLOCK_CODE IS NULL THEN ICL.LUID_NO END) AS B3_PALLETS,
        COUNT(DISTINCT CASE WHEN IC.PV_ID = 'B2' 
               AND      IP.BLOCK_CODE IS NOT NULL THEN ICL.LUID_NO END) AS BLOCKED_B2_PALLETS,
        COUNT(DISTINCT CASE WHEN IC.PV_ID = 'B3' 
               AND      IP.BLOCK_CODE IS NOT NULL THEN ICL.LUID_NO END) AS BLOCKED_B3_PALLETS
         FROM       L2000.ITEM_CARRIER IC
         INNER JOIN L2000.ITEM_UNITS_DEFINITION IUD ON IUD.PV_ID=IC.PV_ID AND IUD.STORER_ID=IC.STORER_ID AND IUD.ITEM_ID=IC.ITEM_ID
         INNER JOIN L2000.ITEM_CARRIER_LUID ICL ON ICL.ITEM_CARRIER_NO=IC.ITEM_CARRIER_NO
         INNER JOIN L2000.ITEM_PROPERTY IP ON IC.PROPERTY_INDEX=IP.PROPERTY_INDEX
         INNER JOIN L2000.ITEM I ON I.ITEM_ID = IC.ITEM_ID AND I.STORER_ID = IC.STORER_ID
               WHERE    IUD.UOM_QTY = ICL.PHYSIC_QTY 
               AND      IUD.UNIT_DEF_ID = 'LU' 
               AND      IC.STORER_ID = 'PG' 
               AND      ICL.PHYSIC_QTY > 0 
               AND      I.ITEM_DESC LIKE '#%' 
               AND      I.ITEM_GROUP_ID IN ('BABYCARE','FEMCARE')

可以简化 SQL 吗？

Possible to simplify SQL?

sql

oracle

simplify