如何在不使用循环的情况下确定 MIPS 中三个整数的最小值

Question

我能够获得用户输入，如我的代码所示，但我无法获得最小的数字。非常感谢...

这是相关说明。

"Write an assembly program to read three 32-bit signed integers from the user. Determine the smallest of these three numbers and display this result. Don’t use loops. Prompt the user for each entered integer."

.data
Msg1: .asciiz "Enter the first integer: "
Msg2: .asciiz "Enter the second integer: "
Msg3: .asciiz "Enter the third integer: "
Msg4: .asciiz "the the smallest numberis: "

.text
     # Print the first message
 li $v0, 4
 la $a0, Msg1
 syscall

 # Prompt the user to enter the first integer
 li $v0, 5
 syscall

 # Store the first integer in $t0
 move $t0, $v0

 # Print the second message
 li $v0, 4
 la $a0, Msg2
 syscall

 # Prompt the user to enter the second integer
 li $v0, 5
 syscall

 # Store the first integer in $t1
 move $t1, $v0

 # Print the third message
 li $v0, 4
 la $a0, Msg3
 syscall

 # Prompt the user to enter the third interger
 li $v0, 5
 syscall

 # Store the first integer in $t0
 move $t2, $v0

 # Determine the smallest Number
 slt $s0, $t1, $t0
 beq $s0, $zero, L1

Answer 1

谢谢大家的回答，我终于确定了最小的数字。该代码在 MARS 上完美运行。

.data
Msg1: .asciiz "Enter the first integer: "
Msg2: .asciiz "Enter the second integer: "
Msg3: .asciiz "Enter the third integer: "

.text
     # Print the first message
 li $v0, 4
 la $a0, Msg1
 syscall

 # Prompt the user to enter the first integer
 li $v0, 5
 syscall

 # Store the first integer in $t0
 move $t0, $v0

 # Print the second message
 li $v0, 4
 la $a0, Msg2
 syscall

 # Prompt the user to enter the second integer
 li $v0, 5
 syscall

 # Store the first integer in $t1
 move $t1, $v0

 # Print the third message
 li $v0, 4
 la $a0, Msg3
 syscall

 # Prompt the user to enter the third interger
 li $v0, 5
 syscall

 # Store the first integer in $t0
 move $t2, $v0

 # Determine the smallest Number
 blt $t0, $t1, L0
 blt $t1, $t0, L3


 li, $v0, 10
 syscall

 L0:
   blt $t0, $t2, L2
   blt $t2, $t0, L3

 L2:
   li $v0, 1
   move $a0, $t0
   syscall
   li, $v0, 10
   syscall

 L3:
   blt $t1, $t2, L4
   blt $t2, $t1, L5

 L4:
    li $v0, 1
    move $a0, $t1
    syscall
    li, $v0, 10
    syscall

 L5:
    li $v0, 1
    move $a0, $t2
    syscall
    li, $v0, 10
    syscall


 li, $v0, 10
 syscall

如何在不使用循环的情况下确定 MIPS 中三个整数的最小值

How to determine the smallest value of three integers in MIPS without using loops

assembly

mips

mips32