shutil.make_archive 没有压缩到正确的目的地
shutil.make_archive not zipping to correct destination
根据下面的代码，我在使用 python 3 shutil.make_archive 函数压缩目录时遇到问题。 .testdir 将被压缩，但它被压缩在 /home/pi，而不是 /home/pi/Backups.
zip_loc = '/home/pi/.testdir'
zip_dest = '/home/pi/Backups/'
shutil.make_archive(zip_loc, 'zip', zip_dest)
谁能解释一下我做错了什么？
阅读文档 here 我想到了：
zip_loc = '/home/pi/.testdir'
zip_dest = '/home/pi/Backups/'
shutil.make_archive(base_dir=zip_loc, root_dir=zip_loc, format='zip', base_name=zip_dest)
来自文档：
base_name is the name of the file to create, including the path, minus any format-specific extension.
root_dir is a directory that will be the root directory of the archive; for example, we typically chdir into root_dir before creating the archive.
base_dir is the directory where we start archiving from; i.e. base_dir will be the common prefix of all files and directories in the archive.
root_dir and base_dir both default to the current directory.
在写存档之前，移动到好目录：
old_path = os.getcwd()
os.chdir(path)
-> 写入存档
写入存档后移回旧目录：
os.chdir(old_path)
根据下面的代码，我在使用 python 3 shutil.make_archive 函数压缩目录时遇到问题。 .testdir 将被压缩，但它被压缩在 /home/pi，而不是 /home/pi/Backups.
zip_loc = '/home/pi/.testdir'
zip_dest = '/home/pi/Backups/'
shutil.make_archive(zip_loc, 'zip', zip_dest)
谁能解释一下我做错了什么？
阅读文档 here 我想到了：
zip_loc = '/home/pi/.testdir'
zip_dest = '/home/pi/Backups/'
shutil.make_archive(base_dir=zip_loc, root_dir=zip_loc, format='zip', base_name=zip_dest)
来自文档：
base_name is the name of the file to create, including the path, minus any format-specific extension.
root_dir is a directory that will be the root directory of the archive; for example, we typically chdir into root_dir before creating the archive.
base_dir is the directory where we start archiving from; i.e. base_dir will be the common prefix of all files and directories in the archive.
root_dir and base_dir both default to the current directory.
在写存档之前，移动到好目录：
old_path = os.getcwd()
os.chdir(path)
-> 写入存档
写入存档后移回旧目录：
os.chdir(old_path)