带有多条轨迹的子图

Question

我正在尝试为以下地块创建子图：

我用于绘图的代码是：

radius_mean1 = df[df['diagnosis']==1]['radius_mean']
radius_mean0 = df[df['diagnosis']==0]['radius_mean']

trace_rm1 = go.Histogram(x = radius_mean1, opacity = 0.75, name = 'malignant')
trace_rm2 = go.Histogram(x = radius_mean0, opacity = 0.75, name = 'benign')

data2 = [trace_rm1,trace_rm2]
layout2 = go.Layout(barmode = 'overlay', title = 'radius mean')
fig2 = go.Figure(data=data2, layout=layout2)

py.iplot(fig2)

另一个情节类似

现在我使用我发现的以下代码来创建子图：

fig.append_trace(fig1['data'][1], 1, 1)
fig.append_trace(fig2['data'][0], 2, 1)
py.iplot(fig)

我明白了：

如何将良性和恶性结果都添加到子图中？我似乎无法编辑 [0] 或 [1] 以同时显示两者，即将前 2 个图准确地放入我的子图中，同时显示恶性和良性，而不仅仅是一个或另一个。

Answer 1

这里的数据并不完整，所以我用一些演示数据来展示。

import numpy as np
import plotly.graph_objs as go
import plotly

a = np.random.normal(0,1,100)
b = np.random.normal(-2,5,100)

c = np.random.normal(0,1,100)
d = np.random.normal(-2,5,100)

fig = plotly.tools.make_subplots(rows=2,cols=1)

trace_rm1 = go.Histogram(x = a, opacity = 0.75, name = 'malignant')
trace_rm2 = go.Histogram(x = b, opacity = 0.75, name = 'benign')
fig.append_trace(go.Histogram(x = a, opacity = 0.75, name = 'benign'),1,1)
fig.append_trace(go.Histogram(x = b, opacity = 0.75, name = 'malignant'),1,1)
fig.append_trace(go.Histogram(x = c, opacity = 0.75, name = 'benign'),2,1)
fig.append_trace(go.Histogram(x = d, opacity = 0.75, name = 'malignant'),2,1)
fig.layout.update(go.Layout(barmode = 'overlay',))

plotly.offline.plot(fig)

带有多条轨迹的子图

subplot with plotly with multiple traces

python

subplot

plotly