传递不同按钮的不同值

Question

我在 activity 1（犯罪和健康）上有 2 个按钮具有不同的 onClickListeners，并且两个函数导致相同的 activity 2...

on activity 2 我想区分用户点击了哪个按钮（无论是犯罪还是健康），以便应用程序可以生成相应的消息..

我正在使用 putExtra 和 bundle 并且还能够从 activity 1 到 activity 2 检索数据但是在 activity 2 上我无法理解哪种 if/else 或者我应该使用 switch 语句，这样我就可以区分用户按下了哪个按钮

ACTIVITY 1 - 轻微

    public class Minor extends Fragment implements View.OnClickListener{

    public String option;

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {

        View view = inflater.inflate(R.layout.minor_view, container, false);
        Button ec = view.findViewById(R.id.ec);
        ec.setOnClickListener(this);

        Button hc = view.findViewById(R.id.hc);
        hc.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Object view=null;
                buttonClicked( (View) view );
            }
        });

        return view;

       }


    @Override
    public void onClick(View view) {

        final Intent intent = new Intent(getActivity(),HelpCall.class);
        Bundle b = new Bundle();
        b.putString(option,"ec");
        intent.putExtras(b);
        startActivity(intent);


    }

   public void buttonClicked (View v)
    {
        final Intent intent = new Intent(getActivity(),HelpCall.class);
        Bundle b = new Bundle();
        b.putString( option,"hc");
        intent.putExtras(b);
        startActivity(intent);

    }
}

Activity 2 - HelpCall

    public class HelpCall extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate( savedInstanceState );
        setContentView( R.layout.activity_help_call );

        Bundle b = getIntent().getExtras();
        String ec = b.getString("ec");
        String hc = b.getString("hc");


        Button sms = (Button) findViewById(R.id.sms);

        sms.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                //   sendSms( "number", "Emergency.. " );
                Toast.makeText( getApplicationContext(), "emergency call crime / health", Toast.LENGTH_LONG ).show();
            }

        });
    }

    private void sendSms(String phoneNumber, String message){
        SmsManager sms = SmsManager.getDefault();
        sms.sendTextMessage(phoneNumber, null, message, null, null);
    }

}

Answer 1

在代码中更改这些内容

public String option;

到

public String option = "value";

和

 Bundle b = getIntent().getExtras();
    String emergency_type = b.getString("value");
    String call_type;
    if(call_type.equalsIgnoreCase("ec"){
              call_type= "ec" ; 
    }
      else{
         call_type = "hc";
       }

    Button sms = (Button) findViewById(R.id.sms);

    sms.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            //   sendSms( "number", "Emergency.. " );
            Toast.makeText( getApplicationContext(), "emergency call " + call_type, Toast.LENGTH_LONG ).show();
        }

    });

Answer 2

i am unable to understand what sort of if/else or switch statement should i use so i could differentiate which button is pressed by user

您实际上可以将按钮 ID 传递给下一个 activity

示例 activity 1

 intent.putExtra("slot", v.getId());

在activity 2

int buttonId = getIntent().getIntExtra("slot", 0);
    switch() {
        case R.id.firstbutton:
            //Do what you want
            break;
        case R.id.secondbutton:
            //Do What you whant
    }

Answer 3

好的，所以您基本上想要从包中放入和获取数据。

思路很简单：

hc.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
              final Intent intent = new Intent(getActivity(),HelpCall.class);
              Bundle b = new Bundle();
              b.putString("option", "hc");
              intent.putExtras(b);
              startActivity(intent);
            }
        });

ec.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
              final Intent intent = new Intent(getActivity(),HelpCall.class);
              Bundle b = new Bundle();
              b.putString("option", "ec");
              intent.putExtras(b);
              startActivity(intent);
            }
        });

而在您的第二个 HelpCall activity 中，您只需要获取传递的值：

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate( savedInstanceState );
    setContentView( R.layout.activity_help_call );
    String data = getIntent().getExtras().get("option");
}

此 data 字符串将包含 ec 或 hc，具体取决于上一个 [=41= 中单击的按钮].

您还可以在代码耦合方面进行一些改进，我写了几篇初学者文章，可能会帮助您解决这个问题。

Answer 4

假设 hc 表示健康，ec 表示犯罪，那么我会这样做。首先，您需要使用一个键将数据传递给第二个 activity，假设键是 "option"，然后在您的两个按钮中都写这个，但在第三行中根据哪个更改第二个值按钮被点击（"ec" 或 "hc"）

final Intent intent = new Intent(getActivity(),HelpCall.class);
Bundle b = new Bundle();
b.putString("option","ec");
intent.putExtras(b);
startActivity(intent);

现在在第二个 activity 你会得到这个值。

Bundle b = getIntent().getExtras();
String option = b.getString("option");

现在在点击侦听器中

sms.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
 //sendSms( "number", "Emergency.. " );
 if(option.contentEquals("ec")){
    //crime clicked do thing here
 }
 else{
   //health clicked do thing here
 }
}
});

传递不同按钮的不同值

passing different vales of different buttons

android

button

android-activity

android-fragmentactivity