带有位置下拉列表的搜索栏包含两个结果 - PHP / mySQL
Search Bar with Location dropdown sumit both results - PHP / mySQL
我有一个基本的搜索栏,可以使用关键字 (k) 搜索我的数据库。我正在尝试同时提交位置和搜索结果,但问题是当我提交搜索结果时,我得到的是 "search.php?k=builder&k=New+York"
而不是 "search.php?k=builder+New+York"
我该如何更正此问题?
HTML
<form action="search.php" method="get" style="margin:0 auto; text-align:center;">
<input type="text" name="k" size="10" style="width:40%;"/>
<div id="the-basics">
<input class="typeahead" type="text" name="k" placeholder="States of USA">
</div>
<input type="submit" value="Search" style="width:100px;">
</form>
搜索栏PHP代码:
<?php
if(!empty($_GET['k'])){
//if search bar is empty
}else{
echo "'<meta http-equiv='refresh' content='0;url=index.php'>";
//redirect back to index.php
}
$k = $_GET['k']; //k stands for keyword
$i = 0;
$terms = explode(" ", $k);
$query ="SELECT * FROM record WHERE ";
foreach ($terms as $each) {
$i++;
if ($i == 1)
$query .= "company_name LIKE '%$each%' " . "OR website LIKE '%$each%' " . "OR email LIKE '%$each%' " . "OR tel LIKE '%$each%' " . "OR description LIKE '%$each%'" . "OR location LIKE '%$each%'" . "OR description LIKE '%$each%'";
}
$connection = mysql_connect('localhost', 'username', 'password');
mysql_select_db('DB_name');
$query = mysql_query($query);
$numrows = mysql_num_rows($query);
if ($numrows > 0){
while ($row = mysql_fetch_assoc($query)) { { ?>
..........search result shows here........
您好,您需要应用一些 JS
<script>
function submitForm(obj){
var search = $('input[name="k"]).val();
var state= $('#state').val();
$('input[name="k"]).val(search+" "+state )
obj.submit();
}
</script>
<form action="search.php" method="get" style="margin:0 auto; text-align:center;" onsubmit=submitForm(this)>
<input type="text" name="k" size="10" style="width:40%;"/>
<div id="the-basics">
<input class="typeahead" type="text" id="state" placeholder="States of USA">
</div>
<input type="submit" value="Search" style="width:100px;">
</form>
我有一个基本的搜索栏,可以使用关键字 (k) 搜索我的数据库。我正在尝试同时提交位置和搜索结果,但问题是当我提交搜索结果时,我得到的是 "search.php?k=builder&k=New+York"
而不是 "search.php?k=builder+New+York"
我该如何更正此问题?
HTML
<form action="search.php" method="get" style="margin:0 auto; text-align:center;">
<input type="text" name="k" size="10" style="width:40%;"/>
<div id="the-basics">
<input class="typeahead" type="text" name="k" placeholder="States of USA">
</div>
<input type="submit" value="Search" style="width:100px;">
</form>
搜索栏PHP代码:
<?php
if(!empty($_GET['k'])){
//if search bar is empty
}else{
echo "'<meta http-equiv='refresh' content='0;url=index.php'>";
//redirect back to index.php
}
$k = $_GET['k']; //k stands for keyword
$i = 0;
$terms = explode(" ", $k);
$query ="SELECT * FROM record WHERE ";
foreach ($terms as $each) {
$i++;
if ($i == 1)
$query .= "company_name LIKE '%$each%' " . "OR website LIKE '%$each%' " . "OR email LIKE '%$each%' " . "OR tel LIKE '%$each%' " . "OR description LIKE '%$each%'" . "OR location LIKE '%$each%'" . "OR description LIKE '%$each%'";
}
$connection = mysql_connect('localhost', 'username', 'password');
mysql_select_db('DB_name');
$query = mysql_query($query);
$numrows = mysql_num_rows($query);
if ($numrows > 0){
while ($row = mysql_fetch_assoc($query)) { { ?>
..........search result shows here........
您好,您需要应用一些 JS
<script>
function submitForm(obj){
var search = $('input[name="k"]).val();
var state= $('#state').val();
$('input[name="k"]).val(search+" "+state )
obj.submit();
}
</script>
<form action="search.php" method="get" style="margin:0 auto; text-align:center;" onsubmit=submitForm(this)>
<input type="text" name="k" size="10" style="width:40%;"/>
<div id="the-basics">
<input class="typeahead" type="text" id="state" placeholder="States of USA">
</div>
<input type="submit" value="Search" style="width:100px;">
</form>