无法反序列化 XML 字符串

Question

我有以下 xml ，我试图按如下方式反序列化，但出现错误：

There was an error reflecting type 'System.Collections.Generic.List`1[MyApp.Models.Field]

下面是我的代码

public class FieldList
{
    [XmlArray("fields")]
    [XmlArrayItem("field")]
    List<Field> Fields { get; set; }
}

public class Field
{
    [XmlAttribute("type")]
    public string Type { get; set; }

    [XmlAttribute("required")]
    public bool Required { get; set; }

    [XmlAttribute("label")]
    public string Label { get; set; }

    [XmlAttribute("name")]
    public string Name { get; set; }

    [XmlElement("option")]
    [JsonProperty("values")]
    public List<Option> Options { get; set; }
}

public class Option
{
    [XmlAttribute("label")]
    public string Label { get; set; }

    [XmlAttribute("value")]
    public string Value { get; set; }

    [XmlAttribute("selected")]
    public bool Selected { get; set; }

    /// <remarks/>
    [XmlIgnore()]
    public bool SelectedSpecified { get; set; }

    [XmlText]
    public string Text { get; set; }
}

var xml =  @"<?xml version=""1.0"" ?>
   <form-template>
    <fields>
        <field type=""select"" required=""true"" label=""Cars"" name=""cars"" >
            <option label=""Toyota"" value=""Toyota"" selected=""true"">Toyota</option>
            <option label=""Nisan"" value=""Nisan"" >Nisan</option>
        </field>
    </fields>
   </form-template>";


 var serializer = new XmlSerializer(typeof(FieldList), new XmlRootAttribute("form-template"));
 var stringReader = new StringReader(xml);
 var xmlFields = (FieldList)serializer.Deserialize(stringReader);

我做错了什么？

* 更新 *

根据下面的评论更改

 public IEnumerable<Option> Options { get; set; }

到

  public List<Option> Options { get; set; }

修复了错误，但现在没有反序列化 - 变量 xmlFields 为空？？？我需要从特定节点读取还是应该无关紧要？

Answer 1

XmlSerializer 无法序列化抽象属性，因此请将 IEnumerable 更改为 List，如下所示，

public IEnumerable<Option> Options { get; set; }

到

public List<Option> Options { get; set; }

您的根元素与您拥有的 XML 结构不匹配。我编辑了 XML 如下，

var xml = "<?xml version=\"1.0\" ?>" +
                    "  " +
                    "    <Fields>" +
                    "        <Field Type=\"select\" Required=\"true\" Label=\"Cars\" Name=\"cars\" >" +
                    "            <option label=\"Toyota\" lalue=\"Toyota\" selected=\"true\">Toyota</option>" +
                    "            <option label=\"Nisan\" value=\"Nisan\" >Nisan</option>" +
                    "        </Field>" +
                    "    </Fields>";

并将代码反序列化为，

XmlSerializer serializer = new XmlSerializer(typeof(List<Field>), new XmlRootAttribute("Fields"));

    var stringReader = new StringReader(xml);
        List<Field> xmlFields = (List<Field>)serializer.Deserialize(stringReader);

现在可以反序列化了。请查看输出，

Answer 2

您需要正确生成要将 xml 序列化到的类。将正确的 XML 不带双 "double quotes" 复制到剪贴板，转到 Visual Studio 中解决方案中的任何 cs 文件。单击 编辑->选择性粘贴-> 将 XML 粘贴为类。这将在您的 cs 文件中正确生成类以进行转换。然后，将这些更改为自动实现的属性，而不是使用私有变量以减少屏幕上的混乱。

用下面类的集合，反序列化为

XmlSerializer serializer = new XmlSerializer(typeof(FormTemplate));
            var xml = @"<?xml version=""1.0"" ?>
   <form-template>
    <fields>
        <field type=""select"" required=""true"" label=""Cars"" name=""cars"" >
            <option label=""Toyota"" value=""Toyota"" selected=""true"">Toyota</option>
            <option label=""Nisan"" value=""Nisan"" >Nisan</option>
        </field>
    </fields>
   </form-template>";
            var stringReader = new StringReader(xml);
            var xmlFields = serializer.Deserialize(stringReader);

自动生成的一组类修改为将属性更改为自动实现的属性。

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute("form-template", Namespace = "", IsNullable = false)]
public partial class FormTemplate
{
    /// <remarks/>
    public Fields fields { get; set; }
}

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class Fields
{
    /// <remarks/>
    public SingleField field { get; set; }
}

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class SingleField
{
    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("option")]
    public Option[] option { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string type { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public bool required { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string label { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string name { get; set; }
  }

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class Option
{
    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string label { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string value { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public bool selected { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlIgnoreAttribute()]
    public bool selectedSpecified { get; set; }

    /// <remarks/>
    [System.Xml.Serialization.XmlTextAttribute()]
    public string Value { get; set; }

}

Answer 3

让我们看看你的代码。

new XmlRootAttribute("form-template") 映射到 <form-template> 节点。

public class Field 映射到 <field 节点。

但没有映射到 <fields> 节点。

添加以下内容class：

public class FieldList
{
    [XmlArray("fields")]
    [XmlArrayItem("field")]
    public List<Field> Fields { get; set; }
}

它应该有效：

var serializer = new XmlSerializer(typeof(FieldList), new XmlRootAttribute("form-template"));
var stringReader = new StringReader(xml);
var xmlFields = (FieldList)serializer.Deserialize(stringReader);

此外，您应该在 Option class 中添加一个属性:

[XmlText]
public string Text { get; set; }

更新。

你可以去掉FieldListclass。但是你必须手动跳过部分 xml 个节点。

List<Field> xmlFields;
var serializer = new XmlSerializer(typeof(List<Field>), new XmlRootAttribute("fields"));

// You can read from a stream or from a StringReader instead of a file
using (var xmlReader = XmlReader.Create("test.xml"))
{
    // Skip <form-template> node
    xmlReader.ReadToFollowing("fields");

    xmlFields = (List<Field>)serializer.Deserialize(xmlReader);
}

将 XmlType 属性添加到您的 class:

[XmlType("field")]
public class Field

无法反序列化 XML 字符串

Unable to deserialize an XML string

c#

xml

xml-deserialization